[英]How do I make decimal.TryParse keep the trailing zeros?
Currently if I do this 目前,如果我这样做
decimal d;
temp = "22.00";
decimal.TryParse(temp, NumberStyles.Any, CultureInfo.InvariantCulture, out d);
Then 'd' turns out as 22. Is there any way I can ensure that trailing zeros don't get wiped out ? 然后'd'变成22.有什么方法可以确保尾随的零没有被消灭掉?
FYI I am using .net 4.0 仅供参考我正在使用.net 4.0
The same code works for me (displaying 22.00, and 22.000 if I change the input string to "22.000"), and as you've specified the invariant culture it shouldn't depend on our respective cultures. 相同的代码适用于我(如果我将输入字符串更改为“22.000”,则显示22.00和22.000),并且当您指定了不变文化时,它不应该依赖于我们各自的文化。
How are you examining the value afterwards? 你之后如何检查价值? If it's in the debugger, I wouldn't be surprised if that were to blame... if you print out d.ToString()
what does that show? 如果它在调试器中,我不会感到惊讶,如果这是责备...如果你打印出d.ToString()
这表示什么?
For example: 例如:
using System;
using System.Globalization;
class Test
{
static void Main()
{
decimal d;
decimal.TryParse("22.00", NumberStyles.Any,
CultureInfo.InvariantCulture, out d);
// This prints out 22.00
Console.WriteLine(d.ToString(CultureInfo.InvariantCulture));
}
}
我会说不,并且只显示带有尾随零的十进制格式,因为22仍然是22.00。
Then 'd' turns out as 22 然后'd'变成了22
And you expect to turn into what? 你期望变成什么? The zeros are still there: 零仍然存在:
Console.WriteLine(d);
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