从表中的datetime列中选择不同的日期

Question

I have a table

id | message | date_posted
1  | testing | 2011-03-08 03:15:13
2  | testing | 2011-03-06 03:15:13
3  | testing | 2011-03-08 03:15:13

And need a query where I return a list of distinct dates in desc order. I tried to formulate a query like so

SELECT DISTINCT CAST(`date_posted` AS DATE) AS dateonly FROM table

This gives me dates but they're not distinct and have duplicates.

Any ideas? (Using php/mysql)

MAJOR EDIT:

Forgot an important piece of information. I'm trying to get unique dates based on month and year.

2011-03-08 03:15:13
2011-03-06 03:15:13
2011-03-02 03:15:13
2011-03-01 03:15:13
2011-02-01 03:15:13

So running the query would only return [2011-03-dd,2011-02-01] (dd being any day)

Apologize for not stating this.

Answer 1

Your query will return unique DATES, as you've specified. If you want to get just unique MONTHS/YEARS, you should either modify you dates in a way, that each date becomes the first day of the month, or you should just go with some string representation like 'YYYY-MM'. Sorry, I can't write you an exact code how to do this, as I do not develop on mysql, but I think this should get you somewhere :)

SELECT DISTINCT YEAR(date_posted), MONTH(date_posted) FROM table

Answer 2

SELECT DATE(`date_posted`) AS dateonly 
FROM   table 
GROUP  BY DATE(`date_posted`) 

Answer 3

Working example

create table dts (dt datetime);
insert dts select '2011-03-08 03:15:13';
insert dts select '2011-03-07 03:15:13';
insert dts select '2011-03-09 03:15:13';
insert dts select '2011-03-08 03:15:13';

select distinct cast(dt as date) from dts;

Output

"cast(dt as date)"
"2011-03-08"
"2011-03-07"
"2011-03-09"

Query for distinct Year-Month

select date(date_format(dt, '%Y-%m-1')) as dt
from dts
group by dt;

Output (the result is a date column, with the day set to '1')

2011-03-01

Answer 4

SELECT DISTINCT date(date_format(COLUMN_NAME, '%Y-%m-%d')) as uniquedates from TABLE_NAME