我的表格包含30个字段，如何将其显示在网页上

Question

I have a mysql table called 'songs' that contains 30 fields and I have a 'song_list.php' page with the width of 800px. I have already implemented it but its seems too crowded. Is there any way to efficiently (easy to read) display the fields.

Answer 1

Record 1
    key    value
    key    value
    key    value
    key    value
    ...

Record 2
    key    value
    key    value
    key    value
    key    value
    ...

Record 3
    key    value
    key    value
    key    value
    key    value
    ...

...

Answer 2

仅显示重要的内容，其余显示在鼠标悬停时或在单独的弹出窗口中。

Answer 3

use something like to make excessively long titles links smaller & only show whats needed title, date,cat, sml desc,price ect

function _substr($str, $length, $minword = 3){
    $sub = '';
    $len = 0;
    foreach (explode(' ', $str) as $word)
    {
        $part = (($sub != '') ? ' ' : '') . $word;
        $sub .= $part;
        $len += strlen($part);
        if (strlen($word) > $minword && strlen($sub) >= $length)
        {
            break;
        }
    }
    return $sub . (($len < strlen($str)) ? '...' : '');
}

Answer 4

您可以将pagination与“ view more选项一起使用

Answer 5

I would triage what the most useful fields are for immediate viewing. Those are the only fields I would display by default. Then have a "more" button of some sort. If clicked, I'm partial to popping up information in a modal dialog. That way any clicks or modifications are still easy to handle via javascript.

If you aren't comfortable rolling your own modal for a project like this, or need somewhere to start, check out this modal dialog roundup. http://komunitasweb.com/2009/03/jquery-modal-box-round-up/

Answer 6

Hi with the same problem I used one jQuery plugin called custom scroller

Check this out