Java整数列表

Question

I am trying to make java go trough a list of numbers. It chooses the first one, gives this as output, waits/sleeps like 2000 milliseconds and then give the next one as output, waits 2000 milliseconds, etc.

They should not be listed behind eachother so when my list is: 10 20 30 40 50

It should not give as output: 10 20 30 40 50. But just 50.

It would be even better if it was able to repeat itself.

So far i tried:

List<Integer> myCoords = new ArrayList<Integer>();
myCoords.add(10);
myCoords.add(20);
myCoords.add(30);
myCoords.add(40);
myCoords.add(50);
Iterator<Integer> myListIterator = someList.iterator(); 
while (myListIterator.hasNext()) {
    Integer coord = myListIterator.next();     
}

But this has no timer, and i am not sure if this will only show '20' or '10 20 30 40 50' as output. And i dont really know how to put a sleep/wait command and a repeat command in this :s (might have overlooked the repeat command if its already in)

Edit Tyvm all, i can go on with the rest of the coding now :)

Answer 1

If you want to rewrite a line on console, print a control character \\r (carriage return).

List<Integer> myCoords = new ArrayList<Integer>();
myCoords.add(10);
myCoords.add(20);
myCoords.add(30);
myCoords.add(40);
myCoords.add(50);
Iterator<Integer> myListIterator = myCoords.iterator(); 
while (myListIterator.hasNext()) {
    Integer coord = myListIterator.next();     
    System.out.print("\r");
    System.out.print(coord);
    Thread.sleep(2000);
}

Answer 2

code that works, but output is:

10
20
30
40
50

so:

    List<Integer> myCoords = new ArrayList<Integer>();
    myCoords.add(10);
    myCoords.add(20);
    myCoords.add(30);
    myCoords.add(40);
    myCoords.add(50);
    for (Integer number : myCoords) {
        System.out.println(number);
        try {
            Thread.sleep(2000);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
    }

Answer 3

To insert a sleep command you can use Thread.sleep(2000). So the code would be:

List<Integer> myCoords = new ArrayList<Integer>();
myCoords.add(10);
myCoords.add(20);
myCoords.add(30);
myCoords.add(40);
myCoords.add(50);
Iterator<Integer> myListIterator = someList.iterator(); 
while (myListIterator.hasNext()) {
    Integer coord = myListIterator.next();    
    System.out.println(coord);
    Thread.Sleep(2000);
}

This would output: 10 20 30 40 50

If you want the numbers after each other you could use: System.out.print(coord +" " ); and if you want to repeat the section you can put it in another while loop.

List<Integer> myCoords = new ArrayList<Integer>();
myCoords.add(10);
myCoords.add(20);
myCoords.add(30);
myCoords.add(40);
myCoords.add(50);
while(true)
    Iterator<Integer> myListIterator = someList.iterator(); 
    while (myListIterator.hasNext()) {
        Integer coord = myListIterator.next();    
        System.out.print(coord + " ");
        Thread.Sleep(2000);
    }
}

This would output: 10 20 30 40 50 10 20 30 40 50 ... and never stop until you kill the program.

Edit: You do have to put the sleep command in a try catch block

Answer 4

So it would become:

List<Integer> myCoords = new ArrayList<Integer>();
myCoords.add(10);
myCoords.add(20);
myCoords.add(30);
myCoords.add(40);
myCoords.add(50);
while(true)
    Iterator<Integer> myListIterator = myCoords.iterator(); 
    while (myListIterator.hasNext()) {
        Integer coord = myListIterator.next();    
        System.out.print("\r" + coord);
        try{
    Thread.sleep(2000);
  }catch(Exception e){
   // handle the exception...
  }
    }
}

Answer 5

Let's use some java 8 feature:

IntStream.iterate(10, x -> x + 10).limit(5)
  .forEach(System.out::println);

If you need to store the numbers you can collect them into a collection eg:

List numbers = IntStream.iterate(10, x -> x + 10).limit(5)
  .boxed()
  .collect(Collectors.toList());

And some delay added:

IntStream.iterate(10, x -> x + 10).limit(5)
  .forEach(x -> {
    System.out.println(x);
    try {
      Thread.sleep(2000);
    } catch (InterruptedException e) {
      // Do something with the exception
    }  
  });