[英]How to show/hide ExtJS.Toolbar button programmatically
I am attempting to show/hide an ExtJS Toolbar button programmatically. 我试图以编程方式显示/隐藏ExtJS工具栏按钮。 I have tried to access the button directly, by ID using:
我试图通过ID直接访问该按钮:
var btn = Ext.get('buttonID'); // I've also tried Ext.query('buttonID')
btn.show();
However, this does not cause the button to be shown. 但是,这不会导致按钮显示。 The toolbar button is defined with the ID with which I am attempting to execute the
show()
method. 工具栏按钮定义了我尝试执行
show()
方法的ID。
Is there a different way for me to access the button, directly? 我是否有不同的方式直接访问按钮? Or, is there a different way to show it (adding/removing CSS attributes, etc.)?
或者,是否有不同的方式来显示它(添加/删除CSS属性等)?
Thank you in advance. 先感谢您。
If you want to show a button, which is not visible, then do 如果要显示一个不可见的按钮,那么就做
// Button definition
var btn = new Ext.Button({
text: 'Press me!',
visible: false,
id: 'myButton'
});
// Now show the button.
var theSameButton = Ext.getCmp('myButton');
btn.setVisible(true);
Is this what you want? 这是你想要的吗?
The 'visible' property only works in 4.1.1+ “可见”属性仅适用于4.1.1+
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