简体   繁体   English

C / C ++转换为const古怪

[英]C/C++ Cast to const weirdness

I have a function declared as: 我有一个函数声明为:

int myFunction(const float** ppArr, const int n, const int m);

and when I call it like so: 当我这样称呼时:

float** ppArr = new float*[5];
// Some initialization of ppArr

int result = myFunction(ppArr, 5, 128);  <<<< Error

and the error is (VS 2008 Express): 而错误是(VS 2008 Express):

error C2664: 'Test_myFunction.cpp' : cannot convert parameter 1 from 'float **' to 'const float **'

WTF? WTF? I'm casting a float** to const float**. 我正在将一个浮动**转换为const float **。 What could possibly go wrong with that ? 可能出现什么问题? :/ :/

Edit: Thank you for incredibly fast responses!!! 编辑:谢谢你非常快速的回复! :) :)

As strange as it seems, it could actually reduce const-correctness in certain obscure cases, allowing you to modify a const object indirectly. 虽然看起来很奇怪,它实际上可以减少某些模糊情况下的const正确性,允许您间接修改const对象。

See http://www.parashift.com/c++-faq-lite/const-correctness.html#faq-18.17 for the full details. 有关详细信息,请参阅http://www.parashift.com/c++-faq-lite/const-correctness.html#faq-18.17

What you can do is convert Foo** to Foo const* const* as that doesn't leave any back doors open. 你可以做的是将Foo**转换为Foo const* const* ,因为它不会让任何后门打开。

Just to add an important observation to the mostly valid answers: things are different for C and C++. 只是为大多数有效的答案添加一个重要的观察结果:C和C ++的情况有所不同。 Whereas the trick works in C++ with Foo const* const* this doesn't work in C, it wouldn't accept this and throw a warning. 虽然这个技巧在C ++中使用Foo const* const*但这在C中不起作用,它不接受这个并发出警告。

In C you'd have to go more complicated ways if you want to have a typesafe cast to Foo const* const* . 在C中,如果你想对Foo const* const*进行类型安全转换,你必须采用更复杂的方法。

float** cannot be converted into const float** . float**无法转换为const float**

It can be converted into float* const* and const float* const* . 它可以转换为float* const*const float* const* Like this: 像这样:

void f(float* const* p) {}

void h(const float* const* p) {}

int main() {
    float** p= new float*[5];
    f(p);
    h(p);
}

Compile it with GCC: http://ideone.com/RrIXl 与GCC编译: http//ideone.com/RrIXl

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM