[英]jQuery elastic easing equation
How can I modify this jQuery easing function to produce a less exaggerated bounce? 如何修改这个jQuery缓动函数以产生一个不那么夸张的反弹?
$.easing.easeOutElasticSingleBounce = function (x, t, b, c, d) {
var s=1.70158;var p=0;var a=c;
if (t==0) return b; if ((t/=d)==1) return b+c; if (!p) p=d*.3;
if (a < Math.abs(c)) { a=c; var s=p/4; }
else var s = p/(2*Math.PI) * Math.asin (c/a);
return a*Math.pow(2,-10*t) * Math.sin( (t*d-s)*(2*Math.PI)/p ) + c + b;
};
I'm looking to produce an easing function that emulates this: 我正在寻找一个模拟这个的缓动函数:
http://sandbox.scriptiny.com/tinyslider2/ http://sandbox.scriptiny.com/tinyslider2/
tinyslider2 uses a similar function that looks something like this: tinyslider2使用类似的功能,看起来像这样:
new Function(this.n+'.slide('+(i==1?t+(12*d):t+(4*d))+','+(i==1?(-1*d):(-1*d))+','+(i==1?2:3)+','+a+')')
But I can't seem to get my head around the math today to fit tinyslider2 equation into the jQuery easing format. 但是我今天似乎无法理解数字,以便将tinyslider2方程符合jQuery缓动格式。 If someone can show me an example, I would appreciate it very much.
如果有人能给我一个例子,我会非常感激。
UPDATE UPDATE
This equation is very close: 这个等式非常接近:
$.easing.custom = function (x, t, b, c, d) {
var s = 1.70158;
if ((t/=d/2) < 1) return c/2*(t*t*(((s*=(1.525))+1)*t - s)) + b;
return c/2*((t-=2)*t*(((s*=(1.525))+1)*t + s) + 2) + b;
}
I just need only the ending bounce without the beginning bounce. 我只需要结束反弹而不开始反弹。
http://timotheegroleau.com/Flash/experiments/easing_function_generator.htm allows you to visually create an easing function. http://timotheegroleau.com/Flash/experiments/easing_function_generator.htm允许您直观地创建缓动功能。 If you toggle the F5/FMX radio button in the top right, it gives the output in JavaScript.
如果您切换右上角的F5 / FMX单选按钮,它会以JavaScript形式输出。
Without knowing exactly the effect you want, this should get you pretty close. 没有确切知道你想要的效果,这应该让你非常接近。
$.easing.tinyslider = function(x, t, b, c, d) {
ts=(t/=d)*t;
tc=ts*t;
return b+c*(-8.1525*tc*ts + 28.5075*ts*ts + -35.105*tc + 16*ts + -0.25*t);
}
Otherwise fiddle around with the easing function generator and try new options or look up http://commadot.com/jquery/easing.php for more resources. 否则,请使用缓动函数生成器并尝试新选项或查找http://commadot.com/jquery/easing.php以获取更多资源。
http://jsfiddle.net/XRF6J/ http://jsfiddle.net/XRF6J/
This was fun to answer, I always wanted to find out how those easing functions worked. 这很有趣,我总是想知道这些缓动功能是如何工作的。
Did you try the jQuery easing plugin ? 你尝试过jQuery easing插件吗?
It adds a lot of new easings (you can try them on the website). 它增加了许多新的缓和(你可以在网站上试试)。
If you can use graceful degradation, I suggest you to take a look at CSS transitions . 如果你可以使用优雅降级,我建议你看看CSS转换 。 It's hardware accelerated, and you can use predefined or custom (with a bezier curve) transitions.
它是硬件加速的,您可以使用预定义或自定义(具有贝塞尔曲线)过渡。
I know this is pretty old, but I needed to make the exact same effect and I used a combination of two easing functions in UI quite successfully. 我知道这已经很老了,但我需要做出完全相同的效果,并且我在UI中使用了两个缓动函数的组合非常成功。
A linear animation for 95% of the transition at 95% of the 'time', then an elastic animation over the remaining 5% at 5% of the 'time' times 16 (this just seemed to look right - a lot of the animation time for this effect is devoted to bouncing around so it needs to be considerably longer). 一个线性动画,95%的过渡时间为95%的'时间',然后弹性动画超过剩下的5%,5%的'时间'时间16(这看起来似乎是正确的 - 很多动画这种效果的时间用于弹跳,因此它需要相当长的时间)。
d = [transition 'distance' or whatever];
t = [transition time ms]
da = d * 0.95;
db = d * 0.05;
ta = t * 0.95;
tb = (t * 0.05) * 16;
var anima = {left: "+="+da+"px"};
var animb = {left: "+="+db+"px"};
$(element).animate(anima,ta).animate(animb,tb);
Quite the workaround, but I couldn't create a bezier formula and I was tearing my hair out trying. 相当多的解决方法,但我无法创建一个bezier公式,我正在试图撕裂我的头发。
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