在项目src中查找URL的基本路径

Question

I need to search for

src="http://www.domain.com/wp-content/uploads/2010/12/6a00e54fa8abf788330147e0622c2e970b-800wi.jpg"

and get

"http://www.domain.com/wp-content/uploads/2010/12/"

Since I never know how long the string is I need to get everything up to the last /

Answer 1

have a look at pathinfo()

ETA due to question edit:

@Chris: what you're trying to do is parse the DOM and pull out the values of src attributes. The easiest and most foolproof way to do this is to use a DOM parser. Have a look at DomDocument::loadHTML and the rest of the DOMDocument class.

Answer 2

使用stripos()

$val = substr($url, 0, stripos($url, '/')); 

Answer 3

how about this:

$str = 'src="http://www.domain.com/wp-content/uploads/2010/12/6a00e54fa8abf788330147e0622c2e970b-800wi.jpg"';
$str = substr($str,5);
$str = substr($str,0,-1);
echo dirname($str)."/";

Answer 4

You can loop the string in reverse and look for the 1st '\\' that you encounter, mark it's position, then copy the string up to that point into another string.

$resulted_path = "";    
for($i = strlen($str)-1 ; ($i>=0) && ($str{$i} != '/') ; $i --);
strncpy($resulted_path, $str, $i);

Do not forget the ';' after the for loop. The resulting string should contain your desired string.

References: charAt | strncpy | strlen