在C / C ++中将月/日/年/时间转换为时间

Question

In C/C++, suppose I have the following values:

int year = 2010;
int month = 6;
int day = 15;
int hour = 14;
int minute = 52;
int seconds = 34;
int microseconds = 141231;

What's the easiest way to convert this to a timeval? I think timeval is time since Jan 1, 1970? But to calculate this manually everytime seems very tedious. What's the easiest (and fastest) way to do this?

Thanks

Answer 1

You can use mktime(3) to convert a struct tm structure into a time_t . After you have the time_t , you can copy it and your microseconds value directly into a struct timeval structure.

Answer 2

您可能想要查看std::mktime() 。