C程序中的bash脚本代码

Question

my problem is the following: I have this bash script:

#!/bin/bash

 IFSBAK=$IFS
 if [ "$TXTEXT" = "" ]; 
 then
   CMD="find . -iname \"*.txt\" -or -iname \"*.text\""
 else
CMDTEMP="find . "
IFS=":"
for i in $TXTEXT
do
    CMDTEMP="${CMDTEMP} -iname \"*.${i}\" -or"
done
IFS=$IFSBAK
CMD=${CMDTEMP%-or}
 fi

 FILES=$(eval $CMD)
 OUTPUT=$1

 for f in $FILES
 do
VAR=$(grep -ae [a-zA-Z0-9] "$f" | tr -cs "[:alnum:]" "\n")
IFS=$' \n\t-?=!*][.\",();\'\`\´:'   
for v in $VAR
do
    echo $v >> "${OUTPUT}"
done
IFS=$' \n\t'
 done

and I need to insert this code inside a C program. I've tried to re-write the all script on a single line testing it directly with the shell and it works, but I'm having problems with quotes and escaping trying to use it as a parameter of the system() call. Can you suggest me a way out?

Thank you for your help

Answer 1

If you really have no choice but to deliver a single binary and you cannot ship the shell script file with the binary consider the following:

1. Include the contents of the script in a single literal
2. During execution of the program, print the contents of the literal to a temporary file. You probably need some strategy to come up with a unique filename.
3. Call the temporary script through system() call
4. Delete the temporary file

However, consider this as a last resort.

Answer 2

Put it into a shell script and invoke the shell script from your C code. Much easier to maintain IMHO.

Answer 3

#define SHELLSCRIPT "
...
write your shell script code here
...
"



   int main()
    {

        system(SHELLSCRIPT);
        return 0;
        //put the bash to C program 
    }