[英]Why is scandir() returning false for directories?
I have a directory named client_images
that has dir_1
, dir_2
and dir_3
as subdirectories. 我有一个名为
client_images
的目录,其中dir_1
, dir_2
和dir_3
作为子目录。 When i run the following: 当我运行以下内容时:
foreach(scandir("client_images") as $key => $value ){
if(is_dir($value)){
echo $value." is a dir.<br>";
}
else{
echo $value." is not a dir.<br>";
}
}
i get : 我得到:
. is a dir. .. is a dir. dir_1 is not a dir. dir_2 is not a dir. dir_3 is not a dir.
Why is php returning false for directories? 为什么php为目录返回false?
You are doing scandir("client_images")
; 你正在做
scandir("client_images")
; the result is bare filenames without the client_images/
path, so it's looking for them in the current directory. 结果是没有
client_images/
path的裸文件名,所以它在当前目录中查找它们。 Naturally, the only directories likely to be in common between .
当然,唯一的目录可能是共同的
.
. 。 and
client_images/
are .
和
client_images/
是.
and ..
, the entries present in all directories. 和
..
,所有目录中的条目。
You can scan directory using DirectoryIterators . 您可以使用DirectoryIterators扫描目录。 Use the below code to to check if a file is a directory or not
使用以下代码检查文件是否是目录
$iterator = new DirectoryIterator('path');
foreach ($iterator as $fileinfo) {
if ($fileinfo->isDir()) {
echo $fileinfo->getFilename() . "\n";
}
}
$mydir = "client_images/";
foreach(scandir($mydir) as $key => $value ){
if(is_dir($mydir . $value)){
echo $value." is a dir.<br>";
}
else{
echo $value." is not a dir.<br>";
}
}
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