this.name 在 javascript 中返回 undefined

Question

I am trying to remotely create an onclick for each <div> (to save typing time).

Here is the window.onload() function:

  window.onload = function() {
    divel = document.getElementsByTagName('div');
    for (var el in divel) {
      divel[el].onmouseover = function() {
        this.style.textDecoration = "underline";
      };
      divel[el].onmouseout = function() {
        this.style.textDecoration = "none";
      };
      divel[el].onclick = function() {
        document.getElementById('game').src = "/games/" + this.name;
      };
    }
  }

The name of every <div> is "flyingsheep" - this value was set by <div name="flyingsheep"> .

When I click the <div> , the iframe "game" takes me to the webpage "/games/undefined" .

Answer 1

This will work. the problem is corrected.

just use : this.attributes["name"].value

window.onload = function() { 
        divel = document.getElementsByTagName('div');
        for(var el in divel){
        window.alert(divel[el].name);
            divel[el].onmouseover = function(){ this.style.textDecoration = "underline"; };
            divel[el].onmouseout = function(){ this.style.textDecoration = "none"; };
            divel[el].onclick = function(){document.getElementById('game').src = this.attributes["name"].value;} 
        }
}

Answer 2

It is hard to say what the problem is for sure, as I don't have access to your test case so I can't see any errors or try to tweak it to make t work, but some problems are:

<div name="flyingsheep"> is not traditional, it is invalid. There is no name attribute for div elements.

I wouldn't be surprised if the JS was throwing an error when you try to set divel.length.onmouseover — don't use for ( foo in bar ) on array like objects, use a normal counter.

My best theory is that you have more div elements then the ones you care about, and it is a click on one of those (one without a name attribute), possibly that contains the one you are aiming to click on) that is firing the JS function.

Answer 3

在 jquery 中，您可以改为使用：

$(this).attr("name");