[英]windows batch file script to pick random files from a folder and move them to another folder
I need a batch script to randomly select X number of files in a folder and move them to another folder.我需要一个批处理脚本来随机 select X 个文件夹中的文件并将它们移动到另一个文件夹。 How do I write a windows batch script that can do this?
如何编写 windows 批处理脚本来执行此操作?
(I'm assuming that your X is known beforehand – represented by the variable $x
in the following code). (我假设您的X事先已知 - 由以下代码中的变量
$x
表示)。
Since you weren't adverse to a PowerShell solution: 由于您不会对PowerShell解决方案产生负面影响:
Get-ChildItem SomeFolder | Get-Random -Count $x | Move-Item -Destination SomeOtherFolder
or shorter: 或更短:
gci somefolder | random -c $x | mi -dest someotherfolder
The following Batch code will do it. 以下批处理代码将执行此操作。 Note that you will need to launch cmd using the following command line:
请注意,您需要使用以下命令行启动cmd:
cmd /v:on
to enable delayed environment variable expansion. 启用延迟环境变量扩展。 Note also that it will pick a random number of files from 0 to 32767 - you will probably want to modify this part to fit your requirements!
另请注意,它将从0到32767选择随机数量的文件 - 您可能需要修改此部件以满足您的要求!
@ECHO OFF
SET SrcCount=0
SET SrcMax=%RANDOM%
FOR %F IN (C:\temp\source\*.*) DO IF !SrcCount! LSS %SrcMax% (
SET /A SrcCount += 1
ECHO !SrcCount! COPY %F C:\temp\output
COPY %F C:\temp\output
)
@echo off & setlocal
set "workDir=C:\source\folder"
::Read the %random%, two times is'nt a mistake! Why? Ask Bill.
::In fact at the first time %random% is nearly the same.
@set /a "rdm=%random%"
set /a "rdm=%random%"
::Push to your path.
pushd "%workDir%"
::Count all files in your path. (dir with /b shows only the filenames)
set /a "counter=0"
for /f "delims=" %%i in ('dir /b ^|find "."') do call :sub1
::This function gives a value from 1 to upper bound of files
set /a "rdNum=(%rdm%*%counter%/32767)+1"
::Start a random file
set /a "counter=0"
for /f "delims=" %%i in ('dir /b ^|find "."') do set "fileName=%%i" &call :sub2
::Pop back from your path.
popd "%workDir%"
goto :eof
:: end of main
:: start of sub1
:sub1
::For each found file set counter + 1.
set /a "counter+=1"
goto :eof
:: end of sub1
:: start of sub2
:sub2
::1st: count again,
::2nd: if counted number equals random number then start the file.
set /a "counter+=1"
if %counter%==%rdNum% (
:: OUTPUT ALERT BOX with FILENAME
MSG * "%fileName%"
)
goto :eof
:: end of sub2
@echo off
setlocal EnableDelayedExpansion
cd \particular\folder
set n=0
for %%f in (*.*) do (
set /A n+=1
set "file[!n!]=%%f"
)
set /A "rand=(n*%random%)/32768+1"
copy "!file[%rand%]!" \different\folder
from Need to create a batch file to select one random file from a folder and copy to another folder 从需要创建批处理文件,从文件夹中选择一个随机文件并复制到另一个文件夹
A sample Powershell code that Moves 1000 Random files From C:\Test\A To C:\Test\B将1000 个随机文件从C:\Test\A移动到C:\Test\B的示例Powershell 代码
$d = gci "C:\Test\A" | resolve-path | get-random -count 1000
Press Enter key and then execute below code按回车键然后执行下面的代码
Move-Item $d -destination "C:\Test\B"
Don't forget to add " mark before and after the path of the folders不要忘记在文件夹路径前后添加"标记
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