[英]How to extract text in php using regex
My Text : 我的文字:
12a49803-713c-4204-a8e6-248e554a352d_ Content-Type: text/plain; charset="iso-8859-6" Content-Transfer-Encoding: base64 DQrn0Ocg0dPH5MkgyszR6sjqySDl5iDH5OfoyuXq5A0KDQrH5OTaySDH5NnRyOrJIOXP2ejlySAx MDAlDQogCQkgCSAgIAkJICA= --_12a49803-713c-4204-a8e6-248e554a352d_ Content-Type: text/html; charset="iso-8859-6" Content-Transfer-Encoding: base64 PGh0bWw+DQo8aGVhZD4NCjxzdHlsZT48IS0tDQouaG1tZXNzYWdlIFANCnsNCm1hcmdpbjowcHg7
I want to extract iso-8859-6 我想提取iso-8859-6
you could do: preg_match('/charset="([^"]+)"/',$string,$m); echo $m[1];
您可以这样做:
preg_match('/charset="([^"]+)"/',$string,$m); echo $m[1];
Edit: In case all need matching (prompted from other answer) modify like this: 编辑:万一所有需要匹配(从其他答案提示)的修改如下:
preg_match_all('/charset="([^"]+)"/',$string,$m); print_r($m);
The regex you are looking for is: 您要查找的正则表达式是:
iso[^"]+
The php code you need is: 您需要的php代码是:
<?php
$subject='12a49803-713c-4204-a8e6-248e554a352d_ Content-Type: text/plain; charset="iso-8859-6" Content-Transfer-Encoding: base64 DQrn0Ocg0dPH5MkgyszR6sjqySDl5iDH5OfoyuXq5A0KDQrH5OTaySDH5NnRyOrJIOXP2ejlySAx MDAlDQogCQkgCSAgIAkJICA= --_12a49803-713c-4204-a8e6-248e554a352d_ Content-Type: text/html; charset="iso-8859-6" Content-Transfer-Encoding: base64 PGh0bWw+DQo8aGVhZD4NCjxzdHlsZT48IS0tDQouaG1tZXNzYWdlIFANCnsNCm1hcmdpbjowcHg7';
$pattern='/iso[^"]+/m';
if (preg_match($pattern, $subject, $match))
echo $match[0];
?>
The output is: 输出为:
iso-8859-6
if you are interested in getting both matches (since you have 2 in the string) and iterate through them you should do something like this. 如果您有兴趣获得两个匹配项(因为字符串中有2个)并对其进行迭代,则应该执行以下操作。 also i used single quotes to not have to escape the quotes inside the regex.
我也使用单引号不必转义正则表达式内的引号。 used ridgerunners suggestions aswell.
也使用了ridgerunners的建议。
preg_match_all('/charset="([^"]+)"/', $subject, $result, PREG_PATTERN_ORDER);
for ($i = 0; $i < count($result[0]); $i++) {
# Matched text = $result[0][$i];
}
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