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XPath获取父元素

[英]XPath get parent element

I have an XPath related question. 我有一个与XPath相关的问题。 I have a list of XML entries like this: 我有这样的XML条目列表:

<NavigationEntry>
<BaseData>
    <Name>Entry Name</Name>
  </BaseData>
  <Relation>
    <RelationEntry isDefault="0">
      <ParentNavigationEntry>456</ParentNavigationEntry>
      <Order>200</Order>
    </RelationEntry>
  </Relation>

<NavigationEntry>
  <BaseData>
    <Name>Entry Name</Name>
  </BaseData>
  <Relation>
    <RelationEntry isDefault="0">
      <ParentNavigationEntry>123</ParentNavigationEntry>
      <Order>200</Order>
    </RelationEntry>
  </Relation>

The question is: how do I get all navigation entries that has a Field ParentNavigationEntry with the value 456. 问题是:如何获取具有值为456的Field ParentNavigationEntry的所有导航条目。

I tried //NavigationEntry//RelationEntry[ParentNavigationEntry="456"] 我尝试了//NavigationEntry//RelationEntry[ParentNavigationEntry="456"]

But this only gives me the RelationEntry Field, but I need the NavigationEntry Field. 但这只给了我RelationEntry字段,但是我需要NavigationEntry字段。

Is it possible to solve this with a single XPath query? 是否可以通过单个XPath查询解决此问题?

The question is: how do I get all navigation entries that has a Field ParentNavigationEntry with the value 456. 问题是:如何获取具有值为456的Field ParentNavigationEntry的所有导航条目。

//NavigationEntry[
   /Relation
      /RelationEntry
         /ParentNavigationEntry = 456
]

Note: Select those NavigationEntry elements and then filter predicate. 注意:选择那些NavigationEntry元素,然后过滤谓词。 Also, when the schema is well known it's not good practice to use // because it traverse the whole descendant tree even after a match. 同样,当模式众所周知时,也不是使用//好习惯,因为即使经过匹配,它也会遍历整个后代树。

Add /ParentNavigationEntry to your XPath.. 将/ ParentNavigationEntry添加到您的XPath。

Example... 例...

//NavigationEntry//RelationEntry[ParentNavigationEntry="456"]//ParentNavigationEntry

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