[英]Git diff --name-only and copy that list
I just want to get a list of changed files between two revisions, which is simple:我只想获取两个修订版之间已更改文件的列表,这很简单:
git diff -–name-only commit1 commit2 > /path/to/my/file
But, what should I write, if I want copy all that listed files to another place?但是,如果我想将所有列出的文件复制到另一个地方,我应该写什么? And I need completely identical directory structure for copied files.
我需要完全相同的目录结构来复制文件。
For example, I have modified and added files:例如,我修改并添加了文件:
/protected/texts/file1.txt
/protected/scripts/index.php
/public/pics/pic1.png
I want to have in /home/changes/
all those changed and added files:我想在
/home/changes/
所有更改和添加的文件:
/home/changes/protected/texts/file1.txt
/home/changes/protected/scripts/index.php
/home/changes/public/pics/pic1.png
尝试以下我已经测试过的命令:
$ cp -pv --parents $(git diff --name-only) DESTINATION-DIRECTORY
The following should work fine:以下应该可以正常工作:
git diff -z --name-only commit1 commit2 | xargs -0 -IREPLACE rsync -aR REPLACE /home/changes/protected/
To explain further:进一步解释:
The -z
to with git diff --name-only
means to output the list of files separated with NUL bytes instead of newlines, just in case your filenames have unusual characters in them. -z
to 与git diff --name-only
意味着输出用 NUL 字节而不是换行符分隔的文件列表,以防万一您的文件名中有不寻常的字符。
The -0
to xargs
says to interpret standard input as a NUL-separated list of parameters. -0
到xargs
表示将标准输入解释为以 NUL 分隔的参数列表。
The -IREPLACE
is needed since by default xargs
would append the parameters to the end of the rsync
command. -IREPLACE
是必需的,因为默认情况下xargs
会将参数附加到rsync
命令的末尾。 Instead, that says to put them where the later REPLACE
is.相反,这表示将它们放在后面的
REPLACE
所在的位置。 (That's a nice tip from this Server Fault answer .) (这是这个 Server Fault answer的一个很好的提示。)
The -a
parameter to rsync
means to preserve permissions, ownership, etc. if possible. rsync
的-a
参数意味着在可能的情况下保留权限、所有权等。 The -R
means to use the full relative path when creating the files in the destination. -R
表示在目标中创建文件时使用完整的相对路径。
Update: if you have an old version of xargs
, you'll need to use the -i
option instead of -I
.更新:如果您有旧版本的
xargs
,则需要使用-i
选项而不是-I
。 (The former is deprecated in later versions of findutils
.) (前者在
findutils
更高版本中已弃用。)
Here's a one-liner:这是一个单行:
List changed files & pack them as *.zip:列出更改的文件并将它们打包为 *.zip:
git diff --name-only | zip patched.zip -@
List last committed changed files & pack them as *.zip:列出最后提交的更改文件并将它们打包为 *.zip:
git diff --name-only HEAD~ HEAD | zip patched.zip -@
zip update.zip $(git diff --name-only commit commit)
#!/bin/bash
# Target directory
TARGET=/target/directory/here
for i in $(git diff --name-only)
do
# First create the target directory, if it doesn't exist.
mkdir -p "$TARGET/$(dirname $i)"
# Then copy over the file.
cp -rf "$i" "$TARGET/$i"
done
https://stackoverflow.com/users/79061/sebastian-paaske-t%c3%b8rholm https://stackoverflow.com/users/79061/sebastian-paaske-t%c3%b8rholm
It works perfectly.它完美地工作。
git diff 1526043 82a4f7d --name-only | xargs zip update.zip
git diff 1526043 82a4f7d --name-only | xargs -n 10 zip update.zip
没有人提到cpio
,它易于键入、创建硬链接并处理文件名中的空格:
git diff --name-only $from..$to | cpio -pld outdir
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