使用java将英国邮政编码拆分为两个主要部分

Question

This regular expression for validating postcodes works perfect

^([Gg][Ii][Rr] 0[Aa]{2})|((([A-Za-z][0-9]{1,2})|(([A-Za-z][A-Ha-hJ-Yj-y][0-9]{1,2})|(([A-Za-z][0-9][A-Za-z])|([A-Za-z][A-Ha-hJ-Yj-y][0-9]?[A-Za-z])))) {0,1}[0-9][A-Za-z]{2})$

but I want to split the postcodes to retrieve the individual parts of the postcode using java.

How can this be done in java?

Answer 1

Here are the official regexes for matching UK postcodes:

http://interim.cabinetoffice.gov.uk/media/291370/bs7666-v2-0-xsd-PostCodeType.htm

If you want to split a found postcode into it's two parts, isn't it simply a question of splitting on whitespace? A UK postcode's two parts are just separated by a space, right? In java this would be:

String[] fields = postcode.split("\\s");

where postcode is a validated postcode and fields[] will be an array of length 2 containing the first and second parts.

If this is to validate user input, and you want to validate the first part, your regex would be:

Pattern firstPart = Pattern.compile("[A-Z]{1,2}[0-9R][0-9A-Z]?");

To validate the second part it is:

Pattern secondPart = Pattern.compile("[0-9][A-Z-[CIKMOV]]{2}");

Answer 2

I realise that it's rather a long time since this question was asked, but I had the same requirement and thought that I'd post my solution in case it helps someone out there :

const string matchString = @"^(?<Primary>([A-Z]{1,2}[0-9]{1,2}[A-Z]?))(?<Secondary>([0-9]{1}[A-Z]{2}))$";

var regEx = new Regex(matchString);
var match = regEx.Match(Postcode);

var postcodePrimary = match.Groups["Primary"];
var postcodeSecondary = match.Groups["Secondary"];

This doesn't validate the postcode, but it does split it into 2 parts if no space has been entered between them.

Answer 3

You can use the Google's recentlly open sourced library for this. http://code.google.com/p/libphonenumber/