Regex / grep查找X深度的文件系统路径

Question

I need a regex/grep/sed/whatever expression that will match

"F:\vol2\home\USERNAME" /grant ... 

and not match on anything like these

"F:\vol2\home\USERNAME\subfolder" /grant ...
"F:\vol2\subfolder\subfoler2" /grant ...
"F:\vol2\home" /grant

Obviously, 'USERNAME' is a variable and needs to be treated as such. I was thinking something like 'home\\\\[A-Za-z]*[^\\\\]' but that's obviously not working.

Answer 1

awk '/home\\[^\\]+\"/{print $1}'

seems to work.

In perl, this works too:

while (<>) {
  print if (/\"F:\\vol2\\home\\[^\\]+\"/);
}

Answer 2

awk -F '\\' -v user=USERNAME 'NF==4 && $3=="home" && $4 ~ "^"user'

在反斜杠上分裂，必须有4个字段，第三个是“home”，第四个字段以用户变量开头

Answer 3

grep'\\ vol2 \\ home \\'$ {USERNAME}'''x2

Answer 4

If your paths are always the first field,

awk '$1~/home\\[^\\]+\"/{print $1}'

Or you can split the first field on \\ and check number of tokens to be 4

$ ruby -ane 'puts $F[0] if $F[0].split("\\").size==4 && /home/' file
"F:\vol2\home\USERNAME"