[英]URL Updating in Drupal and AJAX
I have a select list on my form as the following 我在表单上有一个选择列表,如下所示
<form name="source_form">
<select id="sel_source_zero" name="sel_source_zero">
<?php
$sources = _ajax_get_news_sources();
foreach ($sources as $key => $value) {
print ("<option value=\"$key\">$value</option>\n");
}
?>
</select>
<input type="submit" value="Submit" />
</form>
When the user selects a value from the list, I want to take that value and pass it into a PHP function and return a list of IDs. 当用户从列表中选择一个值时,我想获取该值并将其传递给PHP函数并返回ID列表。 Once I have the source value and the IDs, I want to update my URL with those values.
有了源值和ID后,我想用这些值更新URL。 My entire code is as follows
我的整个代码如下
<?php
$source_var = $_GET['sel_source_zero'];
$action_zero = "/news/date/"._ajax_condition_ids_final_unique_plus_seperated($source_var)."/$source_var";
?>
<script type="text/javascript">
$("#sel_source_zero").change(function (){
$.ajax()
});
</script>
<form name="source_form" method="get">
<select id="sel_source_zero" name="sel_source_zero">
<?php
$sources = _ajax_get_news_sources();
foreach ($sources as $key => $value) {
print ("<option value=\"$key\">$value</option>\n");
}
?>
</select>
<input type="submit" value="Submit" />
</form>
I have approached this problem by first trying to store the selected value ($("sel_source_zero").value()) into a PHP variable using AJAX. 我通过首先尝试使用AJAX将选定的值($(“ sel_source_zero”)。value())存储到PHP变量中来解决此问题。 This is where I got stuck.
这就是我卡住的地方。 I am trying to use $.ajax() function from jQuery appended to Drupal, but I'm not sure how to approach this.
我试图使用附加到Drupal的jQuery中的$ .ajax()函数,但是我不确定如何处理此问题。 If I can some how store the JavaScript variable into PHP variable then I will be able to use my new converted to PHP source variable and pass that into my function to get the list of IDs and then update my URL.
如果可以将JavaScript变量存储到PHP变量中,那么我将能够使用新的转换为PHP的源变量并将其传递给函数以获取ID列表,然后更新URL。 But I'm not even sure if this is the right approach.
但是我什至不确定这是否是正确的方法。 If anyone can point me in the right direction to how I can update my URL with the selected value and returned PHP values returned from a function that uses the selected value as it's parameter, I would greatly appreciate it.
如果有人能正确地指导我如何使用所选值更新URL,以及如何从使用所选值作为参数的函数返回的PHP值中返回PHP值,我将不胜感激。
That is impossible to communicate with the php which has been executed and dead. 与已经执行并已失效的php通信是不可能的。 I'm not 100% sure what you want to do.
我不确定您要做什么。 To guess, you want to redirect to a new url when user select "#sel_cource_zero".
猜测一下,您想在用户选择“ #sel_cource_zero”时重定向到新的URL。
If so (or similar), the answer is as following: 如果是这样(或类似的结果),答案如下:
form.php: form.php:
<script type="text/javascript">
$("#sel_source_zero").change(function (){
var sel = $(this).val();
$.ajax({type:"GET", data: {'sel_source_zero': sel},
url: "ajax.php", dataType: "json", success:
function(result){
location.href = result;
}
});
});
</script>
<form name="source_form" method="get">
<select id="sel_source_zero" name="sel_source_zero">
<?php
$sources = _ajax_get_news_sources();
foreach ($sources as $key => $value) {
print ("<option value=\"$key\">$value</option>\n");
}
?>
</select>
</form>
ajax.php: ajax.php:
<?php
$source_var = $_GET['sel_source_zero'];
$action_zero = "/news/date/"._ajax_condition_ids_final_unique_plus_seperated($source_var)."/$source_var";
echo json_encode($action_zero);
?>
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