如何在不同的命名空间中调用函数？

Question

I have a function called test in namespace buzz .

From this test function i am calling another function called dummy which is inside namespace example .

I get the following error:

Dummy is not a member of example.

Can you please tell me how to communicate between 2 different namespaces?

Thanks

Answer 1

If the namespace is not nested, you should start navigating from the root one, ie:

Instead of:

example::dummy

Write:

::example::dummy

Answer 2

Following code works with gcc (as expected). Your problem must be with something that is not in the question.

#include <iostream>

namespace example
{
  void dummy() { std::cout << "Dummy\n"; }
}

namespace buzz
{
  void test() { example::dummy(); }
}

int main()
{
  buzz::test();
}

Answer 3

You need to provide code for this query. Otherwise just from your question, I guess you are making spelling error:

namespace example {
  void dummy() {}
}
namespace buzz {
  void test () { example::Dummy(); }  // capital 'D' instead of 'd' for dummy
}

Naturally, Dummy is not a member of example. :))