[英]Check if string.at(i) is a whitespace C++
I want to check if a char
( string.at(i)
) is whitespace in C++. 我想检查一下char
( string.at(i)
)是否是C ++中的空格。 How can I do this easily? 我怎么能这么容易做到?
I got this code example, and I was thinking to change the _____
with something, but don't know what. 我得到了这个代码示例,我正在考虑用某些东西改变_____
,但不知道是什么。 I've tried with ' '
, but that didn't work. 我试过' '
,但那没用。
for(int i = 0; i < string.length(); i++)
{
if(string.at(i) == _________)
{
//do something
}
}
#include <cctype>
if (isspace(string.at(i)))
Instead of ==
[something], you want: if (isspace(string.at(i))
(or you might prefer to use std::isspace
). 而不是==
[something],你想要: if (isspace(string.at(i))
(或者你可能更喜欢使用std::isspace
)。
Edit: I should add that depending on what you're doing with the space characters (or what you're going with everything else, depending) you might want to use an algorithm. 编辑:我应该添加,这取决于你正在使用空格字符做什么(或者你要用其他所有东西,取决于你),你可能想要使用算法。 Just for example, if you wanted to create a copy of your string with all the whitespace characters removed, you could use: 例如,如果您想创建一个删除了所有空白字符的字符串副本,您可以使用:
std::remove_copy_if(s.begin(), s.end(), std::back_inserter(new_string), isspace);
Unrepentant C programmers migrating to C++ would semi-automatically use: 迁移到C ++的不悔改的C程序员会半自动使用:
#include <cctype>
if (std::isspace(string.at(i)))
...
It is quite likely to be the correct even for C++ programmers. 即使对于C ++程序员来说,它也很可能是正确的。
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