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SQL Server:如何在查询中使用子字符串?

[英]SQL Server: How to use substring in a query?

i have this kind of row: 我有这样的行:

 [Arturo Ochando] <20> 

But i want only: 但我只想要:

 Arturo Ochando 

How can i do that ? 我怎样才能做到这一点 ?

And how use this in a 'select' operation ? 以及如何在“选择”操作中使用它?

update: i would like to find the first and the last '[' ']' and catch only what is inside there. 更新:我想找到第一个和最后一个'['']'并只捕获其中的内容。

Example: 例:

voice: English version) [Cobalt Claw] 声音:英文版)[钴爪]

return 返回

Cobalt Claw 钴爪

Best regards, Valter Henrique. 最好的问候,Valter Henrique。

Get text between first [ and next ] . 在first [和next ]之间获取文本。

-- cte for test data
;with actor_character(character) AS
(
  select 'voice: English version) [Cobalt Claw]' union all
  select 'voice: English version) [Cobalt Claw' union all
  select 'voice: English version)  Cobalt Claw]' union all
  select 'voice: English version) ]Cobalt Claw[' union all
  select 'voice: English version)  Cobalt Claw'
)
select *,
  case
    -- Test for not valid positions
    when Start.Pos = 1 or Stop.Pos = 0
    then character
    else substring(character, Start.Pos, Stop.Pos-Start.Pos)
  end
from actor_character
  cross apply (select charindex('[', character)+1) as Start(Pos)
  cross apply (select charindex(']', character, Start.Pos)) as Stop(Pos)

Get text between first [ and last ] . 获取first [和last ]之间的文本。

-- cte for test data
;with actor_character(character) AS
(
  select 'voice: English version) [Cobalt Claw]' union all
  select 'voice: English version) [Cobalt Claw' union all
  select 'voice: English version)  Cobalt Claw]' union all
  select 'voice: English version) ]Cobalt Claw[' union all
  select 'voice: English version) [Cobalt]Claw]' union all
  select 'voice: English version)  Cobalt Claw'
)
select *,
  case
    -- Test for not valid positions
    when Start.Pos = 0 or Stop.Pos = 0 or Start.Pos > len(character)-Stop.Pos
    then character
    else substring(character, Start.Pos+1, len(character)-Stop.Pos-Start.Pos)
  end

from actor_character
  cross apply (select charindex('[', character)) as Start(Pos)
  cross apply (select charindex(']', reverse(character))) as Stop(Pos)
select substring(field, charindex('[', field) + 1, charindex(']', field) - charindex('[', field) - 1)

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