[英]Bash - argument not working
Hello I am running a javac command (lstf is a file) 您好我正在运行一个Javac命令(lstf是一个文件)
javac @$lstf
For some reason, I get an error saying javac: file not found: path/to/dir/*.java
. 出于某种原因,我收到一条错误消息,指出
javac: file not found: path/to/dir/*.java
。 Whenever I type the args in manually in Terminal javac works. 每当我在Terminal javac works中手动输入args时。
Here is the code: 这是代码:
mkdir "$out"
cd src
scan
"$cc" $cflags -d "../$out" @${lstf}
rm -rf $lstf
cd ../
scan is the function that generates all the paths in the file $lstf - it works fine scan是在文件$ lstf中生成所有路径的函数-工作正常
You need to say javac @foo
, and lstf
= foo
? 您需要说
javac @foo
和lstf
= foo
吗?
Whenever you are in a situation where variable names are hard to decipher, you can use ${var}
syntax instead of just $var
: 每当您遇到难以解析的变量名的情况时,都可以使用
${var}
语法,而不仅仅是$var
:
javac @${lstf}
如果文件路径存储在lstf变量中,则将其命名为
javac "$lstf"
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