使用RegEx查找没有数字的所有单词

Question

I found this code to get all words of a string,

static string[] GetWords(string input)
{
    MatchCollection matches = Regex.Matches(input, @"\b[\w']*\b");

    var words = from m in matches.Cast<Match>()
                where !string.IsNullOrEmpty(m.Value)
                select TrimSuffix(m.Value);

    return words.ToArray();
}

static string TrimSuffix(string word)
{
    int apostrapheLocation = word.IndexOf('\'');
    if (apostrapheLocation != -1)
    {
        word = word.Substring(0, apostrapheLocation);
    }

    return word;
}

1. Please describe about the code.
2. How can I get words without figures?

Answer 1

2 How can I get words without figures?

You'll have to replace \\w with [A-Za-z]

So that your RegEx becomes @"\\b[A-Za-z']*\\b"

And then you'll have to think about TrimSuffix(). The regEx allows apostrophes but TrimSuffix() will extract only the left part. So "it's" will become "it".

Answer 2

In

MatchCollection matches = Regex.Matches(input, @"\b[\w']*\b");

the code is using a regex that will look for any word; \\b means border of word and \\w is the alpha numerical POSIX class to get everything as letters(with or without graphical accents), numbers and sometimes underscore and the ' is just included in the list along with the alphaNum. So basically that is searching for the begining and the end of the word and selecting it.

then

var words = from m in matches.Cast<Match>()
                    where !string.IsNullOrEmpty(m.Value)
                    select TrimSuffix(m.Value);

is a LINQ syntax, where you can do SQL-Like queries inside your code. That code is getting every match from the regex and checking to see if the value is not empty and to get it without spaces. Its also where you can add your figure validation.

and This:

static string TrimSuffix(string word)
    {
        int apostrapheLocation = word.IndexOf('\'');
        if (apostrapheLocation != -1)
        {
            word = word.Substring(0, apostrapheLocation);
        }

        return word;
    }

is removing the ' of the words who have it and getting just the part that is before it

ie for don't word it will get only the don