如何使用PyGTK获取任务栏的大小和位置？

Question

Is there any way to get the position and size of the taskbar on Windows with PyGTK?

If not, is there at least a way to determine the free client area on a specific monitor? (In other words, the area the taskbar does not occupy?)

Answer 1

Slightly neater (but windows only) as this creates a dynamic pair of variables which you can then used to adjust the offset of your remaining code;

import win32gui

#discover where top left corner of active screen is
#return is a dictionary list of keys and values
monitors = win32api.EnumDisplayMonitors()
display1 = win32api.GetMonitorInfo(monitors[0][0])

#from the Work key, select the first and second values
x_adj=(display1['Work'][0])
y_adj=(display1['Work'][1])

Then, in the remainder of your code use these adjustments to refine your navigation clicks. In my case I am moving around a window using pyautogui

import pyautogui

#just move the mouse to a position
pyautogui.moveTo(x=103+x_adj, y=235+y_adj)

#move and click the mouse
pyautogui.click(x=103+x_adj, y=235+y_adj)

In your case you will want to create the top left corner of the new window at (or relative to) the co-ordinates of (x_adj,y_adj)

Answer 2

You can maximize a window, and check its geometry after it was maximized. Something like this (works both on Windows and Linux):

import gtk

size = (10, 10)
def expose(widget, *args):
    global size
    size = widget.get_size()
    if size != (10, 10):
        gtk.main_quit()

win = gtk.Window()
win.resize(*size)
win.connect('expose-event', expose)
win.show()
win.maximize()
gtk.main()
print size

This is somewhat hackish, but I'm not sure if there is a portable way (without using Win32 API if you are on Windows) to do this.