短语中每个单词的首字母大写

Question

Ok, I'm trying to figure out how to make a inputed phrase such as this in python ....

Self contained underwater breathing apparatus

output this...

SCUBA

Which would be the first letter of each word. Is this something to do with index? and maybe a .upper function?

Answer 1

This is the pythonic way to do it:

output = "".join(item[0].upper() for item in input.split())
# SCUBA

There you go. Short and easy to understand.

LE : If you have other delimiters than space, you can split by words, like this:

import re
input = "self-contained underwater breathing apparatus"
output = "".join(item[0].upper() for item in re.findall("\w+", input))
# SCUBA

Answer 2

Here's the quickest way to get it done

input = "Self contained underwater breathing apparatus"
output = ""
for i in input.upper().split():
    output += i[0]

Answer 3

#here is my trial, brief and potent!
str = 'Self contained underwater breathing apparatus'
reduce(lambda x,y: x+y[0].upper(),str.split(),'')
#=> SCUBA

Answer 4

Pythonic Idioms

• Using a generator expression over str.split()
• Optimize the inner loop by moving upper() to one call at outside of the loop.

Implementation:

input = 'Self contained underwater breathing apparatus'
output = ''.join(word[0] for word in input.split()).upper()

Answer 5

Another way

input = 'Self contained underwater breathing apparatus'

output = ''.join(item[0].capitalize() for item in input.split())

Answer 6

def myfunction(string):
    return (''.join(map(str, [s[0] for s in string.upper().split()])))

myfunction("Self contained underwater breathing apparatus")

Returns SCUBA

Answer 7

Another way which may be more easy for total beginners to apprehend:

acronym = input('Please give what names you want acronymized: ')
acro = acronym.split() #acro is now a list of each word
for word in acro:
    print(word[0].upper(),end='') #prints out the acronym, end='' is for obstructing capitalized word to be stacked one below the other
print() #gives a line between answer and next command line's return

Answer 8

I believe you can get it done this way as well.

def get_first_letters(s):
    return ''.join(map(lambda x:x[0].upper(),s.split()))

Answer 9

s = "Self contained underwater breathing apparatus" 
for item in s.split():
    print item[0].upper()

Answer 10

一些列表理解爱：

 "".join([word[0].upper() for word in sentence.split()])

Answer 11

Why no one is using regex? In JavaScript, I would use regex so I don't need to use the loop, please find Python example below.

import re
input = "Self-contained underwater & breathing apparatus google.com"
output = ''.join(re.findall(r"\b(\w)", input.upper()))
print(output)
# SCUBAGC

Please note that the above regex /\\b(\\w)/g uses \\b word boundary and \\w word so it will match position between an alphanumeric word character and non-word character so for example “&” is not matched and ".com" “c” is matched and also "s" and "c" is matched on "self-contained"

Alternative Regex using lookahead and lookbehind:

• /(?!a\\s)\\b[\\w]|&/g Excluding " a " and including "&"
• /(?<=\\s)[\\w&]|^./g Any word character and "&" after every whitespace. This prevents matching "c" on .com but also prevents matching "c" on "self-contained"

Code snippet
Regex 1 , Regex 2 , Regex 3