在Django中创建包含动态数据的3列HTML表

Question

I am trying to create a dynamic HTML table with 3 columns and 3 rows. Each column will have 3 records from the database so there will be 9 total records displayed (if they have 9 friends. otherwise just however many they have). I am doing this to mainly display small user profile pictures with their friends' usernames on the users homepage. Its going to be a list of 9 of their friends. I am using Django and cannot seem to find a tutorial showing how to display only 3 records per row if I retrieve 9 total records. Any help would be appreciated whether it be a link to a tutorial or info on how to solve this issue. Thanks!

Answer 1

you can use the forloop.counter and do something like:

<table>
    <tr>
{% for person in people %}
        <td>{{ person }}</td>
    {% if not forloop.last and forloop.counter == 3 or forloop.counter == 6 %}
    </tr>
    <tr>
    {% endif %}
{% endfor %}
    </tr>
</table>

or roll a custom template tag. One here looks like its doing what you want.

looks like this SO question is related:

Render one queryset into 2 div columns (django template)

[EDIT] : should be "counter" not "count"

Answer 2

此代码段在此上下文中也可能很有用： 将表序列分组为TABLE的行和列

Answer 3

您可以使用{% if friends|length == 9 %}来检查您是否有9条记录。