使用setTimeout运行的停止功能
[英]stop function that run with setTimeout
问题描述
I want stop my function that run with setTimeout and do not show image followed mouse. 
我想停止使用setTimeout运行的函数，并且不显示跟随鼠标的图像。 I want do that with button click, how do that? 我想通过单击按钮做到这一点，怎么办？ my code: 我的代码：
<html xmlns="http://www.w3.org/1999/xhtml">
<head id="Head1" runat="server">
<title></title>
<script type="text/javascript">
var trailimage = ["test.gif", 100, 99];
var offsetfrommouse = [-25, -25];
var displayduration = 0;
function truebody() {
return (!window.opera && document.compatMode && document.compatMode != "BackCompat") ? document.documentElement : document.body;
}
function hidetrail() {
var x = document.getElementById("trailimageid").style;
x.visibility = "hidden";
document.onmousemove = "";
}
function followmouse(e) {
var xcoord = offsetfrommouse[0];
var ycoord = offsetfrommouse[1];
if (typeof e != "undefined") {
xcoord += e.pageX;
ycoord += e.pageY;
}
else if (typeof window.event != "undefined") {
xcoord += truebody().scrollLeft + event.clientX;
ycoord += truebody().scrollTop + event.clientY;
}
var x = document.getElementById("trailimageid").style;
x.left = xcoord + "px";
x.top = ycoord + "px";
}
alert("obj_selected = true");
document.onmousemove = followmouse;
if (displayduration > 0)
setTimeout("hidetrail()", displayduration * 1000);
</script>
</head>
<body>
<form id="form1" runat="server">
<img alt="" id="trailimageid" src="Pictures/sides/sides-not-clicked.gif" border="0" style="position: absolute; visibility: visible; left: 0px;
top: 0px; width: 50px; height: 50px"/>
</form>
</body>
</html>
3 个解决方案
解决方案1
4 2011-04-26 06:14:38
var foobarTimeout = setTimeout(foobar, 1000);
...
clearTimeout(foobarTimeout);
See: 看到：
https://developer.mozilla.org/en/DOM/window.setTimeout https://developer.mozilla.org/en/DOM/window.setTimeout
https://developer.mozilla.org/en/DOM/window.clearTimeout https://developer.mozilla.org/en/DOM/window.clearTimeout
解决方案2
1 已采纳 2011-04-26 06:14:56
Save the return value of setTimeout , which is a "handle" for the timer, and when you want to cancel it, call clearTimeout with that value. 保存setTimeout的返回值，该值是计时器的“句柄”，并且要取消它时，请使用该值调用clearTimeout 。
So in your code, you'd declare a timerHandle variable somewhere appropriate, then set it here: 因此，在您的代码中，您将在适当的位置声明一个timerHandle变量，然后在此处进行设置：
if (displayduration > 0)
timerHandle = setTimeout("hidetrail()", displayduration * 1000);
...and then create a button click handler: ...然后创建按钮click处理程序：
function cancelTimeoutOnClick() {
if (timerHandle) {
clearTimeout(timerHandle);
timerHandle = 0;
}
}
Off-topic : It's almost never best practice to pass strings into setTimeout , that's an implicit eval . 离题 ：将字符串传递到setTimeout几乎从来不是最佳实践，这是一个隐式的eval 。 In your case, just pass the function reference: 在您的情况下，只需传递函数引用即可：
if (displayduration > 0)
timerHandle = setTimeout(hidetrail, displayduration * 1000);
// ^--- Difference here (no quotes, no parentheses)
解决方案3
0 2011-04-26 06:15:02
you use timeout like > 您使用超时>
var myTimeout = setTimeout(yourfunction);
and then you can cancel it > 然后您可以取消它>
clearTimeout(myTimeout);
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