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将部分专用模板作为模板参数传递

[英]Passing partially specialized template as a template parameter

I have a class template, expecting some other template as a parameter: 我有一个类模板,期望一些其他模板作为参数:

template<
    class Key, 
    template <typename K,template <typename T> class Allocator> class Policy
>
class container {
     Policy<Key,Allocator>* _policy;
     //some code here
};

and usually i use it with the policy class like this: 通常我将它与策略类一起使用,如下所示:

template <class Key,template <typename T> class Allocator> class policy {
    //some code
};

but what if i have to pass additional template parameter to policy class? 但是如果我必须将额外的模板参数传递给策略类呢? Something like: 就像是:

template <time_t Age,class Key,template <typename T> class Allocator> class policy_3 {
    //some code
};

What can i do, to allow users of that class, pass the Age paratemeter without touching others? 我该怎么办,允许该类用户通过Age paratemeter而不接触其他人? For example: 例如:

typedef container<key_type,policy_3<100500> > containerWithAge;

You have two options: binding, and rebinding. 您有两个选择:绑定和重新绑定。

In binding, you adapt the ternary policy into a binary one, as expected by the template-template parameter Policy : 在绑定中,您可以根据模板模板参数Policy预期将三元策略调整为二进制Policy

template <typename Key, template <typename T> class Allocator>
struct policy_3_100500 : ternary_policy<100500,Key,Allocator> {};

and use policy_3_100500 instead of policy_3<100500> . 并使用policy_3_100500而不是policy_3<100500>

To be closer to the syntax you're shooting for, you can use a nested class: 为了更接近您正在拍摄的语法,您可以使用嵌套类:

template <time_t Age>
struct policy_3 {
    template <typename Key, template <typename T> class Allocator>
    struct type : ternary_policy<Age,Key,Allocator> {};
};

and use policy_3<100500>::type instead of policy_3<100500> . 并使用policy_3<100500>::type而不是policy_3<100500>

The only way to get exactly the syntax you want is to move the ::type into the class using the policy. 获得所需语法的唯一方法是使用策略将::type移动类中。 That's the second option: rebinding (this is also used in std::allocator, btw). 这是第二个选项:重新绑定(这也用于std :: allocator,btw)。 In this case, you pass the Policy as a normal template parameter, and assume a template metafunction, say bind , to exist: 在这种情况下,您将Policy作为普通模板参数传递,并假设模板元函数(例如bind )存在:

template <time_t Age>
struct policy_3 {
    template <typename Key, template <typename T> class Allocator>
    struct bind : ternary_policy<Age,Key,Allocator> {};
};

While structually identical to the second option, the difference lies in who calls bind : In the first option (binding), it's the user of the policy class (by passing policy<100500>::type explicitly). 虽然结构上与第二个选项相同,但区别在于谁调用 bind :在第一个选项(绑定)中,它是策略类的用户(通过明确地传递policy<100500>::type )。 Here, it's the class using the policy: 在这里,它是使用该策略的类:

template <typename Key, typename Policy>
struct container {
    typename Policy::template bind<Key,std::allocator<Key>> * _policy;
    // ...
}:

As a general note, Policy classes are not usually passed as template-template arguments, but as normal template arguments (precisely because they may have a varying number of arguments themselves). 总的来说,Policy类通常不作为模板模板参数传递,而是作为普通的模板参数传递(正是因为它们本身可能有不同数量的参数)。 The classes using the policy then assume a certain inner structure (typedefs, functions, meta functions, constants) to be present in the policy, of which bind is just an example. 然后,使用策略的类假定在策略中存在某个内部结构(typedef,函数,元函数,常量),其中bind只是一个示例。

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