用PHP显示MySQL数据

Question

I am trying to display all records from my table CarCollection using the following code. Right now I am only able to return the 1st record. how can I achieve this?

$connection = mysql_connect("localhost","USER_NAME","PASSWORD");
if (!$connection)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("DATABASE_NAME", $connection);

$result = mysql_query("SELECT * FROM CarCollection");
$row = mysql_fetch_array($result);

mysql_close($connection);

Answer 1

<?php

$connection = mysql_connect("localhost","USER_NAME","PASSWORD");
if (!$connection)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("DATABASE_NAME", $connection);

$result = mysql_query("SELECT * FROM CarCollection");
while($row = mysql_fetch_array($result)){

echo $row[0];
echo $row[1];
}


mysql_close($connection);
?>

Answer 2

Above is correct - I normally have another part to the while loop to make sure that the result is still set:

<?php

$connection = mysql_connect("localhost","USER_NAME","PASSWORD");
if (!$connection)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("DATABASE_NAME", $connection);

$result = mysql_query("SELECT * FROM CarCollection");
while($result && $row = mysql_fetch_array($result)){

echo $row[0];
echo $row[1];

//Or You can Name the Columns
echo $row['name'];


}


mysql_close($connection);
?>

Answer 3

mysql_query是一种好的编程习惯之后，关闭mysql连接。

Answer 4

Add a while loop to the mysql_fetch_array(); thats it...