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搜索 NSDictionary 对象的 NSArray

[英]Searching NSArray of NSDictionary objects

I've contacts array where each contact is a dictionary.我有联系人数组,其中每个联系人都是字典。

Each contact has a key "contact_type" which is an NSNumber.每个联系人都有一个键“contact_type”,它是一个 NSNumber。 Contact type basically represents whether its a Facebook, LinkedIn or Mail contact etc. I've a search array which holds only NSNumber of contact_type's.联系人类型基本上代表它是 Facebook、LinkedIn 还是邮件联系人等。我有一个搜索数组,它只包含 NSNumber 的contact_type。

What I want is to make a temporary array of contacts which I want to search using my search array.我想要的是制作一个临时的联系人数组,我想使用我的搜索数组进行搜索。

I am facing trouble using NSPredicate to create searched contacts array.我在使用 NSPredicate 创建搜索联系人数组时遇到了麻烦。 Can some one guide me on how to do it?有人可以指导我怎么做吗?

NSArray *contacts = ...; //your array of NSDictionary objects
NSPredicate *filter = [NSPredicate predicateWithFormat:@"contact_type = 42"];

NSArray *filteredContacts = [contacts filteredArrayUsingPredicate:filter];

After this, filteredContacts will contain only the contacts whose contact_type is 42 .之后, filteredContacts将只包含contact_type42的联系人。

If you need to search for more than one kind of contact_type , then simply use an OR in the predicate:如果您需要搜索不止一种contact_type ,那么只需在谓词中使用OR

filter = [NSPredicate predicateWithFormat:@"contact_type = 42 OR contact_type = 23"];

This solution work cool for me.这个解决方案对我来说很酷。

//NSDictionary Format //NSDictionary 格式

{
 18=(
     {
        content="Great Avijit",
        id=abc
     }
 ),
13=(
     {
        content="Stack Overflow is cool",
        id=abc
      }
 ),
} 

//Step 1 //步骤1

 -(void)filterContentForSearchText:(NSString *)searchText
   {
        [self.filterResultArray removeAllObjects];

         NSPredicate *namePredicate = [NSPredicate predicateWithFormat:@"(content contains[cd] %@)", searchText];//from_user.name
           //other

         for (NSMutableDictionary *key in self.messageAll) {

             NSArray *array=[self.messageAll objectForKey:key];
              array=[array filteredArrayUsingPredicate:namePredicate];

             if ([array count]==0) {
                     [self.filterResultArray removeObject:key];
             }
             else{

               if ([self.filterResultArray containsObject:key]) {

                }
                else{
                      [self.filterResultArray addObject:key];
                }

            }

      }


      //Reload table view
      [self.tableView reloadData];

  }

//Step 2: numberOfRowsInSection //第2步:numberOfRowsInSection

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section {


    if (self.searchController.active && ![self.searchController.searchBar.text isEqualToString:@""]) {
        return [self.filterResultArray count];
    }else{
        return [keyArray count];//keyArray hold all key of original dict
    }

}

//Step 3: In cellForRowAtIndexPath method //第 3 步:在 cellForRowAtIndexPath 方法中

 NSString *key = [self.filterResultArray objectAtIndex:indexPath.row];
  NSDictionary *dictionary = [[self.messageAll objectForKey:key] lastObject];//self.messageAll is original dict

Dave's answer above is perfect, I am just adding here what I learned after spending 3 hours of my night sleep.上面戴夫的回答是完美的,我只是在这里添加我花了 3 个小时的夜间睡眠后学到的东西。

When you are trying to search string values within dictionary of an array yo need to use predicate something like this:当您尝试在数组的字典中搜索字符串值时,您需要使用如下谓词:

NSPredicate *filter = [NSPredicate predicateWithFormat:[NSString stringWithFormat:@"Title CONTAINS[cd] '%@' OR Description CONTAINS[cd] '%@'", searchText, searchText]];

Don't forget wrapping your values with '', this was the only thing that cost me all the time.不要忘记用''包装你的价值观,这是唯一让我付出代价的事情。 Here is my final search function这是我最后的搜索 function

-(void)searchTerm : (NSString*)searchText {
    if (searchText!=nil && searchText.length) {
        NSPredicate *filter = [NSPredicate predicateWithFormat:[NSString stringWithFormat:@"Title CONTAINS[cd] '%@' OR Description CONTAINS[cd] '%@'", searchText, searchText]];
        self.reasonDetailArray = [self.unfilteredReasonDetailArray filteredArrayUsingPredicate:filter];
    }else{
        self.reasonDetailArray = self.unfilteredReasonDetailArray;
    }
    [self.tableView reloadData];
}

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