通过 gcc Makefile 的两个可执行文件

Question

Here is my Makefile:

# Makefile

CC=gcc
CFLAGS=-ansi -Wall

prog1: prog1.o
prog2: prog2.o

clean:
   rm -f prog1.o prog2.o

Which works and creates a 'prog1' executable from prog1.c, but it does not build prog2 at all. How would I make it do this?

Answer 1

Create an all target and put it before both prog1 and prog2 :

all: prog1 prog2

Answer 2

You can make prog2 to make prog2 seperately, or add a all: prog1 prog2 rule to make both automatically.