用破折号替换空格并从字符串中删除前缀

Question

I'm using this to remove spaces and special characters and convert characters to lowercase:

''.join(e for e in artistName if e.isalnum()).lower()

I want to:

• replace spaces with -

• if the string starts with the word the , then it

So that, for instance, The beatles music! would become beatles-music .

Answer 1

artistName = artistName.replace(' ', '-').lower()
if artistName.startswith('the-'):
    artistName = artistName[4:]
artistName = ''.join(e for e in artistName if e.isalnum() or e == '-')

Answer 2

It sounds like you want to make a machine readable slug. Using a library for this function will save you lots of headache. python-slugify does what you are asking for and a bunch of other things you might not have even thought of.

Answer 3

This would be best done with a bunch of regex-es so you can easily add to it over time.

Not sure of the python syntax but if it was perl you'd do something like:

s/^The //g;  #remove leading "The "
s/\s/-/g;    #replace whitespaces with dashes

It looks like python has a nice little howto for regexes: http://docs.python.org/howto/regex.html

Answer 4

Starting in Python 3.9 , you can also use removeprefix :

'The beatles music'.replace(' ', '-').lower().removeprefix('the-')
# 'beatles-music'