增强互斥锁，条件，scoped_lock，我在这里使用错吗？

Question

class MyClass
{
public:
    void PushMessage(MyMessage m) // Thread 1 calls this
    {
        boost::mutex::scoped_lock lock(mMutex);
        mQueue.push_back(m);
        mCondition.notify_one();
    }

    MyMessage PopMessage()
    {
        boost::mutex::scoped_lock lock(mMutex);
        while(mQueue.empty())
            mCondition.wait(lock);

        MyMessage message = mQueue.front();
        mQueue.pop_front();
        return message;
    }

    void foo() // thread 2 is running this loop, and supposed to get messages
    {
        for(;;)
        {
            MyMessage message = PopMessage();

            do_something(message);
        }
    }
private:
    std::deque<MyMessage> mQueue;

    boost::mutex mMutex;
    boost::condition mCondition;
};

When I run the code, PushMessage is called, and foo() is waiting on PopMessage() , but PopMessage never returns.

What does do_something here is not irrelevant I think.

What am I doing wrong here? Strangely, the above code worked fine under mac, but I'm having trouble on linux.
boost version is 1.44.0

Thank you

Answer 1

Rather than letting the scope of the lock object expire before it unlocks, you could try to manually unlock the mutex in PushMessage() before you unblock the waiting thread, ie,

void PushMessage(MyMessage m) // Thread 1 calls this
{
    boost::mutex::scoped_lock lock(mMutex);
    mQueue.push_back(m);

    lock.unlock(); // <== manually unlock

    mCondition.notify_one();
}

That way when thread 2 unblocks, there will be no "cross-over" time where thread 1 contains the lock, and thread 2 is trying to obtain a lock on your mutex. I don't see why that would create problems, but again, at least you won't have thread 2 trying to call lock.lock() while thread 1 still contains the lock.

Answer 2

I think you need 2 mutex objects, one is for synchronizing method call in different threads, one is for condition wait. You mixed them.