[英]AmazonS3, how to check if the upload succeeded?
I wrote a short test code in Java to upload a PDF file generated in memory. 我用Java编写了一个简短的测试代码来上传在内存中生成的PDF文件。 In this test code I just use a dummy byte array, but in the real use I will put a generated PDF (max 2-3 pages) in that byte array.
在这个测试代码中我只使用一个虚拟字节数组,但在实际使用中,我将在该字节数组中放置一个生成的PDF(最多2-3页)。 Everything works: the file gets uploaded and the permissions set.
一切正常:文件上传并设置权限。
However since I've a PutObjectResult returned, I was wondering how I'm supposed to check it. 然而,因为我已经返回PutObjectResult,我想知道我应该如何检查它。 Or is it enough to look for the exceptions AmazonClientException and AmazonServiceException?
或者是否足以查找AmazonClientException和AmazonServiceException异常?
In other words: How to check that the upload succeded and didn't corrupt my data? 换句话说: 如何检查上传是否成功并且没有损坏我的数据?
String bucket = "mybucket.example.com";
String fileName = "2011/test/test.pdf";
AmazonS3 client = new AmazonS3Client(new BasicAWSCredentials(
"accessKey", "secretKey"));
byte[] contents = new byte[] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 };
InputStream stream = new ByteArrayInputStream(contents);
ObjectMetadata meta = new ObjectMetadata();
meta.setContentLength(contents.length);
meta.setContentType("application/pdf");
PutObjectResult res = client.putObject(bucket, fileName, stream, meta);
client.setObjectAcl(bucket, fileName, CannedAccessControlList.PublicRead);
I've looked the source code of AWS and debugged it and discovered the following: 我查看了AWS的源代码并对其进行了调试并发现了以下内容:
In other words, to answer my own question, it's enough to listen for the exceptions because also the MD5 of the data uploaded is checked, so if there was a corruption an exception would be raised. 换句话说,为了回答我自己的问题,它就足以监听异常,因为还检查了上传数据的MD5,因此如果存在损坏,则会引发异常。
AmazonClientException and AmazonServiceException are unchecked exceptions, so it's important to remember to listen for them since the compiler won't force you to. AmazonClientException和AmazonServiceException是未经检查的异常,因此记住监听它们非常重要,因为编译器不会强制您这样做。
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