正则表达式问题 - 排除某些字符

Question

If I want to exclude /* in regex how would I write it?

I have tried:

[^/[*]]
([^/][^*])

But to no avail...

Answer 1

您必须not /匹配not / ，或/ followed by not * ：

([^/]|/[^*])+/?

Answer 2

Use a negative lookahead to check that, if the input contains / , it does not contain / followed by /* . In JavaScript , x not followed by y would be x(?!y) , so:

• Either the input contains no / : new RegExp('^[^/]*$') , or
• Any / found must not be followed by * : new RegExp('^/(?!\\\\*)$') (note, the * must be escaped with a \\\\ since * is a special character.

To combine the two expressions:

new RegExp('^([^/]|/(?!\\*))*$')

Answer 3

In Java following Pattern should work for you:

Pattern pt = Pattern.compile("((?<!/)[*])");

Which means match * which is NOT preceded by / .

TEST CODE

String str = "Hello /* World";
Pattern pt = Pattern.compile("((?<!/)[*])");
Matcher m = pt.matcher(str);
if (m.find()) {
    System.out.println("Matched1: " + m.group(0));
}
String str1 = "Hello * World";
m = pt.matcher(str1);
if (m.find()) {
    System.out.println("Matched2: " + m.group(0));
}

OUTPUT

Matched2: *

Answer 4

Can't you just deny a positive match? So the kernel is just "/*", but the * needs masking by backslash, which needs masking itself, and the pattern might be followed or preceded by something, so .* before and after the /\\\\* is needed: ".*/\\\\*.*" .

val samples = List ("*no", "/*yes", "yes/*yes", "yes/*", "no/", "yes/*yes/*yes", "n/o*")  
samples: List[java.lang.String] = List(*no, /*yes, yes/*yes, yes/*, no/, yes/*yes/*yes, n/o*)

scala> samples.foreach (s => println (s + "\t" + (! s.matches (".*/\\*.*"))))                   
*no true
/*yes   false
yes/*yes    false
yes/*   false
no/ true
yes/*yes/*yes   false
n/o*    true

Answer 5

See http://mindprod.com/jgloss/regex.html#EXCLUSION

eg [^"] or [^wz] for anything but quote and anything but wxyz