如何分辨布局以50/50间隔所有内容？

Question

I have a vertical linear layout with two ListViews. I want the top ListView to take up 50% of the screen. I want the bottom listivew to take up 50% of the screen. How can I do this in XML?

Answer 1

The following layout should work

<LinearLayout
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:orientation="vertical"
    >

    <ListView
        android:id="@+id/list1"
        android:layout_width="fill_parent"
        android:layout_height="0dp"
        android:layout_weight="1"
        />

    <ListView
        android:id="@+id/list2"
        android:layout_width="fill_parent"
        android:layout_height="0dp"
        android:layout_weight="1"
        />

</LinearLayout>

How this works:

• Initially both lists have no height
• After measuring everything with a height, the remaining height (in this case all of it as there are no other views with a specified height or wrap_content ) is divided up between all the views with no height and a layout_weight
• The height of each view will be (layout_weight of View) / (Sum of layout_weights in parent ViewGroup)
• In this case, (Sum of layout_weights in parent ViewGroup) = 2 and (layout_weight of View) = 1 for each ListView , so each ListView occupies 1/2 of the available space

Answer 2

将Vertical LinearLayout设置为具有height:fill_parent ，然后将weight of each ListView to "1" eg android:layout_weight="1"的weight of each ListView to "1" eg android:layout_weight="1"设置weight of each ListView to "1" eg android:layout_weight="1"