简体   繁体   English

获取弹出窗口的DOM元素以进行jQuery操作

[英]Get DOM elements of a popup for jQuery manipulation

I am creating a popup as follows: 我正在创建一个弹出窗口如下:

   var comet = {

        popup: null, 

        newPopup: function(windowsname, w, h){
            this.popup = window.open(windowsname, windowsname, 'width=' + w + ',height=' + h);
            var self = comet;
            var logOut= null;
            $(this.popup.document).ready(function(){
                logOut = self.popup.document.getElementById('logout');
                console.log(logOut);
                $(logOut).live('click', function(){
                    alert('HELLO');
                    return false;
                })
            })
        },

        some_function: function(){
             //calling it here:
             this.newPopup('index.php',1120,550);
        }
    }

The logOut sometimes (usually on the 1st window open) returns null. logOut有时(通常在第一个窗口打开)返回null。 Also, the click handler never goes through and the original click handler operates. 此外,单击处理程序永远不会通过,原始单击处理程序也会运行。

How do I overwrite the real click handler of the popup? 如何覆盖弹出窗口的真实点击处理程序?
Both pages are on my site, so there should be no cross site issues.. 这两个页面都在我的网站上,所以应该没有跨站点问题..

Here is a fiddle that shows a little of what I am trying to do: http://jsfiddle.net/maniator/K2B3q/ 这是一个小提琴,展示了我想要做的一些事情: http//jsfiddle.net/maniator/K2B3q/

Tested and working in Firefox 4 and Chrome 11. Check it out. 在Firefox 4和Chrome 11中经过测试和使用。 请查看。

$(function()
{
    var comet =
    {
        popup: null,  
        newPopup: function(url, w, h)
        {
            this.popup = window.open(url, url, 'width=' + w + ',height=' + h);
            var self = this;

            this.popup.onload = function ()
            {
              var doc = this.document,
                  script = doc.createElement('script');
              script.src = 'http://ajax.googleapis.com/ajax/libs/jquery/1.5.2/jquery.min.js';
              script.onload = function ()
              {
                  function setup()
                  {
                      $('#logout').click(function () { alert('It worked!'); });
                  }

                  script = doc.createElement('script');
                  script.textContent = "(" + setup.toString() + ")();";
                  doc.body.appendChild(script);
              };

              doc.head.appendChild(script);
            };
        },

        foo: function()
        {
            this.newPopup('http://jsbin.com/amuza3/2', 600, 400);
        }
    };

    $('#clickme').click(function ()
    {
        comet.foo();
    });
});

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM