[英]Unexpected output in C from float multiply
I am performing a multiplication and addition operation in C and am getting the wrong result. 我在C中执行乘法和加法运算,并得到错误的结果。
I am performing the following operation: 我正在执行以下操作:
#include <stdio.h>
#include <strlib.h>
#include <math.h>
int main()
{
float** fpimag;
float** fpreal;
// Some code to assign fpimag and fpreal
// fpimag and fpreal are two dimensional arrays that are
// passed by reference to some functions to assign data to them
allocatememory(&fpimag,&fpreal);
storedata(&fpimag,&fpreal);
autofunction(&fpimag,&fpreal);
} // main()
void autofunction(float*** fpimag,float***fpreal) {
float expreal;
float expimag;
expreal = cos((*afph_correct)[row][column]);
expimag = sin((*afph_correct)[row][column]);
(*fpimag)[row][column] = (*fpimag)[row][column] * expreal + (*fpreal)[row][column] * expimag;
printf("Operation looks like this\n");
printf("%f*%f + %f*%f\n",(*fpimag)[row][column],expreal,(*fpreal)[row][column],expimag);
printf("The value is %f\n",(*fpimag)[row][column]);
} // autofunction
This is the output I get: 这是我得到的输出:
Operation looks like this
-0.003095*-0.431162 + 0.000027*-0.902275
The value is 0.003865
However the correct answer should be: 但是正确的答案应该是:
0.0013101
Thank you! 谢谢!
Try long double, more precise than float: http://en.wikipedia.org/wiki/Long_double 尝试长双精度,比浮点精度更精确: http : //en.wikipedia.org/wiki/Long_double
Please note that you should change your printf (%Lf for long double) 请注意,您应该更改您的printf(长整数为%Lf)
I'm surprised it doesn't crash. 我很惊讶它没有崩溃。 In fact I'm surprised it even compiles. 实际上我很惊讶它甚至可以编译。 I would be gobsmacked if it compiles without warnings. 如果它编译时没有警告,我将很震惊。
(The first two may be covered by code not shown - the other three look to be definite problems) (前两个可能被未显示的代码覆盖-其他三个看起来是确定的问题)
Look at the following two lines: 请看以下两行:
(*fpimag)[row][column] = (*fpimag)[row][column] * expreal +
(*fpreal)[row][column] * expimag;
printf("%f*%f + %f*%f\n",fpimag,expreal,fpreal,expimag);
Can't you see that fpimag is not the same as (*fpimag)[row][column]? 您看不到fpimag与(* fpimag)[row] [column]不同吗? (and the same with fpreal) You are writing pointer to float pointer values, not the values the pointers are pointing to. (与fpreal相同),您正在将指针写为浮点指针值,而不是指针所指向的值。 Try this instead: 尝试以下方法:
float imag = (*fpimag)[row][column];
float real = (*fpreal)[row][column];
(*fpimag)[row][column] = imag * expreal + real * expimag;
printf("%f*%f + %f*%f\n",imag,expreal,real,expimag);
Hey I found the problem it was pretty obvious: 嘿,我发现问题很明显:
I was overwriting the value of fpreal and then trying to use it in another calculation. 我正在覆盖fpreal的值,然后尝试在其他计算中使用它。
Thus I did: 因此,我做到了:
(*fpreal)[row][column] = (*fpreal)[row][column]*expreal - (*fpimag)[row][column]*expimag;
(*fpimag)[row][column] = (*fpimag)[row][column]*expreal + (*fpreal)[row][column]*expimag;
I have since updated the code so that the values of fpreal and fpimag are stored in some temporary variables and use those for the calculations, as such: 此后,我更新了代码,以便将fpreal和fpimag的值存储在某些临时变量中,并将其用于计算,如下所示:
oldreal = (*fpreal)[row][column];
oldimag = (*fpimag)[row][column];
(*fpreal)[row][column] = oldreal*expreal - oldimag*expimag;
(*fpimag)[row][column] = oldimag*expreal + oldreal*expimag;
Thank you everybody for your assistance though! 谢谢大家的帮助!
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