[英]Get the values from each td
I am using phpQuery to get the data from elements. 我使用phpQuery从元素中获取数据。
I'm trying to get the values from first td
, seconds td
and href
link from each tr
. 我试图从每个
tr
第一个td
,秒td
和href
链接获取值。
<table>
<tr class="A2">
<td> Text 1 </td>
<td> Text 2 </td>
<td> Text 3 </td>
<td> <a href="linkhere1"> Text 131</a> </td>
</tr>
<tr class="A2">
<td> Text 4 </td>
<td> Text 5 </td>
<td> Text 6 </td>
<td> <a href="linkhere2"> Text 123213</a> </td>
</tr>
<tr class="A2">
<td> Text 7 </td>
<td> Text 8 </td>
<td> Text 9 </td>
<td> <a href="linkhere3.php"> Text 213213 </a> </td>
</tr>
</table>
How to do this? 这个怎么做? I have tried:
我努力了:
<?
require('phpQuery.php');
$file = file_get_contents('test.txt', true);
$html = phpQuery::newDocument($file);
foreach($html->find('.A2') as $tag) {
echo pq('td'); // problem here?
}
?>
I guess you have them switched.. 我想你有他们切换..
foreach(pq('.A2') as $tag) {
$tds = pq($tag)->find('td');
}
To get a value from each td, you can iterate over it inside: 要从每个td获取值,您可以在其中迭代:
foreach(pq('.A2') as $tag) {
foreach(pq($tag)->find('td') as $td) {
// stuff
}
}
pq()
would return a list of matching nodes (your <td>
tags, in this case). pq()
将返回匹配节点的列表(在这种情况下,您的<td>
标签)。 You have to iterate over that list: 你必须迭代该列表:
foreach(pq('td') as $td) {
... do something ...
}
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