如何根据ID使用Jquery在两个Div之间添加Div？

Question

If I have these objects:

<div id='1'></div>
<div id='2'></div>
<div id='3'></div>
<div id='4'></div>
<div id='5'></div>

I have a textbox:

<input type="text">

Where I type in the value: 3.5 to dynamically make (I have the code for this, the next part I need help with):

<div id='3.5'></div>

How can I attach it in this order below, without first checking to see the value of every div on the page?

<div id='1'></div>
<div id='2'></div>
<div id='3'></div>
<div id='3.5'></div>
<div id='4'></div>
<div id='5'></div>

Using:

$('#What Goes Here If I Dont know the elements on the page?').after('<div id='3.5'>Hey</div>');

Any help is appreciated,

Taylor

Answer 1

IDs in the DOM should not start with a number (they would not be valid).
They should start with a character A-Za-z and then they can have numbers, - and _ following.

but if you want to go your route try this:

var div = $("<div id='3.5'></div>");
div_id_after = Math.floor(parseFloat(div.get(0).id));

$('#'+div_id_after).after(div);

Here is a fiddle demo: http://jsfiddle.net/maniator/DPMV5/

Answer 2

这有什么问题？

  $('#3').after('<div id='3.5'>Hey</div>');

Answer 3

Firstly IDs aren't allowed to start with a number.

Ignoring that, if you are only allowing integers, it's easy, just take 1 from the value and insert it, then renumber the rest. Otherwise you'll have to walk the DOM to check the values of the others first.

Answer 4

that comparision to add is arithmetic, so unfortunelly you need to iterate over the divs you could do this. maybe you should do padding, like 3 = 300000, so 3.5 is 3500000, to do a best comparision.

Answer 5

Maybe something like that would work:

var text = yourTextBox.value;
if(var number = Number(text))
{
    $('#'+Math.floor(number)).after('<div id='+text+'>Hey</div>');
} 
else alert("wrong number");

But you should probably check first (with a regex) that the text within the textbox is a legitimate number…

Answer 6

updated. thanks Neal.

http://jsfiddle.net/FB8xG/3/

var newValue = 3.5;

var oldValue = Math.floor(newValue); //3

var oldValueID = ('#' + oldValue);
var newValueID = ('<div id="' + newValue + '">' + newValue + '</div>');

$(oldValueID).after(newValueID);

Answer 7

Live Demo

var input = "3.5";
var parent = Math.floor(input);
var dest = $('#div-'+parent);

dest.after(dest.clone().attr('id','div-'+input).text(input));

Note: This will only work once between integers. A more robust method DOES require looking at the IDs of all divs within the destination.