[英]Using if statement in where clause
With if in a where statement I'm trying to get all rows where datetime is larger then NOW(), but if type = 'economy', i would like to constraint it to only show if datediff between datetime and NOW() is larger than 14 days. 如果在where语句中我试图获取datetime大于NOW()的所有行,但是如果type ='economy',我想限制它只显示datetime和NOW()之间的datediff是否更大超过14天。
Something like: 就像是:
Select type,date(datetime) as date
from tbl1
where datetime > NOW()
IF(type = 'economy') && datediff(datetime,NOW()) > 14
order by datetime desc
I've tried with case when also, but can't figure it out... 我也曾尝试过案例,但无法弄清楚......
You can just separate the criteria into 2 different comparisons: 您可以将标准分为两种不同的比较:
select type,date(datetime) as date
from tbl1
where (datetime > NOW() AND type <> 'economy') OR
(datediff(datetime, NOW()) > 14 AND type = 'economy')
order by datetime desc
(Not checked for syntax errors, but the idea should be right...) (没有检查语法错误,但这个想法应该是正确的...)
WHERE ((type <> 'economy') AND (datetime > now)) OR ((type = 'economy') AND (datediff(datetime,NOW()) > 14)
“
SELECT type, date(datetime) AS date
FROM tbl1
WHERE ( type <> 'economy' AND datetime > NOW() )
OR ( type = 'economy' AND datediff(datetime, NOW()) > 14 )
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