使用Java从CSV文件中搜索特定的列值

Question

I want to search by column value and retrieve that particular row from a csv file using java. Suppose I provide "ABC123" than the result should come in this format "ABC123, SW, Php" .

Here is the csv file format:

Employee_Id, Designation, Domain

ABC123, SW, Php

XYZ456, SW, Java

So how do I search any clue. Thanks .

Answer 1

Read the file line by line with a BufferedReader wrapped around a FileReader . Stop when you hit a line that startsWith the thing you're looking for. Close the reader and return the line.

Edit:
There's no fancy searching or optimising you can do here, unless the CSV file has some sort of order you haven't mentioned. You just have to read each line until you find the one you want.

Answer 2

/**
 * returns a string which is comma separate column values for matching row otherwise null. 
 * @param searchColumnIndex
 * @param searchString
 * @return
 * @throws IOException 
 * 
 */
public String searchCsvLine(int searchColumnIndex, String searchString) throws IOException {
    String resultRow = null;
    BufferedReader br = new BufferedReader(new FileReader("somefile.csv"));
    String line;
    while ( (line = br.readLine()) != null ) {
        String[] values = line.split(",");
        if(values[searchColumnIndex].equals(searchString)) {
            resultRow = line;
            break;
        }
    }
    br.close();
    return resultRow;
}

In your case the call will be String result = searchCsvLine(0, "ABC123");

Answer 3

使用OpenCSV读取CSV文件 ，然后查找并返回所需的值。

Answer 4

public class Example4 {
  public static void main(String[] args) throws Exception {
    String splitBy = ",";
    BufferedReader br = new BufferedReader(new FileReader("C:\\\sample1.csv"));
    String line;
    while((line = br.readLine()) != null) {
      String[] b = line.split(splitBy);
      System.out.println(b[0]);
    }
    br.close();
  }
}