[英]Need some help with regular expressions (php)
For example, I have the following code : 例如,我有以下代码:
$string = "adf gggg eere value aaaa bbb (10) value
ddttt ggg www (20) value ddttt ggg www dddd (40) ";
preg_match("/(value).*(\(\d+\))/is", $string, $result);
var_dump($result[2]); // outputs 40.
I'm trying to get the first value (10). 我想要获得第一个值(10)。 The code above outputs 40 which makes sense, but not what I want.
上面的代码输出40有意义,但不是我想要的。 The string pattern is : word "value", then a number of any characters, then "(", integer, ")".
字符串模式是:单词“value”,然后是多个任何字符,然后是“(”,整数,“)”。 It seems that I'm missing something obvious... I haven't worked too much with regular expressions, but I believe it can be solved somehow with
?<!value
, no luck so far though. 似乎我错过了一些明显的东西...我没有用正则表达式做太多工作,但我相信它可以用某种方式解决
?<!value
,但到目前为止没有运气。
Thanks for any help. 谢谢你的帮助。
.*
is greedy, so it will match as many characters as possible, you want .*?
.*
是贪婪的,所以它会匹配尽可能多的字符,你想要的.*?
which will match the minimum characters needed to complete the match: 这将匹配完成匹配所需的最小字符:
/(value).*?(\(\d+\))/
What's wrong with your regex is that .* is greedy, and tries to matchs as many letters as possible. 你的正则表达式有什么问题。*是贪婪的,并试图匹配尽可能多的字母。
preg_match("#value.*?\((\d+)\)#is", $string, $result);
But you can make it faster by using a negative class: 但是你可以通过使用负面类来加快速度:
preg_match("#value[^(]+\((\d+)\)#is", $string, $result);
.*?value.*?\((\d+)\).*
Being *? 存在 *? a reluctant match.
不情愿的比赛。
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