[英]displaying records from mysql in ul and li format with php
i want to display the mysql's fetched results with php and html in unordered list and list format as like http://www.miniclip.com/games/en/ . 我想用无序列表和列表格式显示mysql的获取结果,如php和html,如http://www.miniclip.com/games/en/ 。 you can see in the all games categories in the footer in alphabetical order.
您可以按字母顺序在页脚中的所有游戏类别中查看。 the same requirement i do have.
我有同样的要求。 i guess i have written the logic its working fine.
我想我写的逻辑工作正常。 but i am unable to represent it properly.
但我无法正确代表它。 you can see in the following link above the footer.
您可以在页脚上方的以下链接中看到。 http://www.playtoongames.com/play1 ...
http://www.playtoongames.com/play1 ...
code: 码:
<?php
$gameQuery = mysql_query ("SELECT name, LEFT(name, 1) AS first_char FROM games WHERE UPPER(name) BETWEEN 'A' AND 'Z' OR name BETWEEN '0' AND '9' ORDER BY name");
$current_char = '';
while ($gameRow = mysql_fetch_assoc($gameQuery)){
if ($_SESSION['lang'] == 'fr'){
$description = $gameRow['description_fr'];
}else{
$description = $gameRow['description'];
}
?>
<div style='float:left' title="<img src='<?php echo $gameRow['sitePath'];?>games/images/<?php echo $gameRow['img_100x75'];?>' width='230' height='112' class='thumb' alt='<?php echo $gameRow['name'];?>'/>" class='tooltip'>
<ul>
<li>
<a href='<?php echo $gameRow['sitePath'];?>play/<?php echo str_replace(' ','_',$gameRow['name']);?>'><?php echo $gameRow['name'];?></a>
</li>
</ul>
</div>
can anybody look into this... 任何人都可以看看这个......
Regards, sam. 问候,山姆。
On the Playtoons site, each <li>
is in its' own individual <ul>
- this means you're creating a new list for each item: 在Playtoons网站上,每个
<li>
都在其自己的个人<ul>
- 这意味着您要为每个项目创建一个新列表:
<ul>
<li>13 More Days</li>
</ul>
<ul>
<li>A Bikers Heaven</li>
</ul>
What you should be doing is using one <ul>
which contains all the items as <li>
s: 你应该做的是使用一个
<ul>
,它包含所有项目<li>
s:
<ul>
<li>13 More Days</li>
<li>A Bikers Heaven</li>
</ul>
Well, I think the key is that there are 6 columns, which just means you'll need to break your array into 6 different parts. 好吧,我认为关键是有6列,这意味着你需要将你的阵列分成6个不同的部分。
Here's some psuedocode: 这是一些伪代码:
$pArr = $from_sql_array; // I'll let you take care of that.
$itmCount = count($pArr);
$itmsPerCol = ceil($itmCount / 6.0);
for ($ii=0; $ii < 6; $ii++)
{
$pCol = array_slice($pArr, $itmsPerCol * $ii, $itmsPerCol);
echo '<ul class="floatleft"><li>'.implode("</li>\n<li>",$pCol).'</li></ul>';
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.