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打印出在指向字符串的指针中获得的数据时出错

[英]Error in printing out the data obtained in pointer to character strings

I am trying to call an interface function and print out the resulting values. 我正在尝试调用接口函数并打印出结果值。 The function prototype contains pointers to character string as arguments. 函数原型包含指向字符串的指针作为参数。 When I print out the resulting values I receive some strange symbols. 当我打印出结果值时,会收到一些奇怪的符号。 Is my below approach correct? 我的以下方法正确吗?

int interfacecall(char *a, char *b ...);

char * a= "Testdata";
char b [4098];

result= interfacecall(a,b);

//different value is returned in b via function implementation in a third party dll.

printf(b);

Your printf is not that safe. 您的printf不太安全。 It should be : 它应该是 :

printf("%s", b);  //corrected - safe!

In C++, you can also use std::cout as: 在C ++中,您还可以将std::cout用作:

std::cout << b; //its simpler - must include<iostream>

Make sure that b is a null-terminated c-string, otherwise it wil print garbage and may crash your program. 确保b是一个以null终止的c字符串,否则它将打印垃圾,并可能使程序崩溃。 Null-terminated string means it must end with \\0 . 空终止的字符串意味着它必须以\\0结尾。 Something like this: 像这样:

b[slen] = '\0'; //you may have to do this explicitly!

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