sqlalchemy：如何通过一个查询连接多个表？

Question

I have the following SQLAlchemy mapped classes:

class User(Base):
    __tablename__ = 'users'
    email = Column(String, primary_key=True)
    name = Column(String)

class Document(Base):
    __tablename__ = "documents"
    name = Column(String, primary_key=True)
    author = Column(String, ForeignKey("users.email"))

class DocumentsPermissions(Base):
    __tablename__ = "documents_permissions"
    readAllowed = Column(Boolean)
    writeAllowed = Column(Boolean)

    document = Column(String, ForeignKey("documents.name"))

I need to get a table like this for user.email = "user@email.com" :

email | name | document_name | document_readAllowed | document_writeAllowed

How can it be made using one query request for SQLAlchemy? The code below does not work for me:

result = session.query(User, Document, DocumentPermission).filter_by(email = "user@email.com").all()

Thanks,

Answer 1

Try this

q = Session.query(
         User, Document, DocumentPermissions,
    ).filter(
         User.email == Document.author,
    ).filter(
         Document.name == DocumentPermissions.document,
    ).filter(
        User.email == 'someemail',
    ).all()

Answer 2

A good style would be to setup some relations and a primary key for permissions (actually, usually it is good style to setup integer primary keys for everything, but whatever):

class User(Base):
    __tablename__ = 'users'
    email = Column(String, primary_key=True)
    name = Column(String)

class Document(Base):
    __tablename__ = "documents"
    name = Column(String, primary_key=True)
    author_email = Column(String, ForeignKey("users.email"))
    author = relation(User, backref='documents')

class DocumentsPermissions(Base):
    __tablename__ = "documents_permissions"
    id = Column(Integer, primary_key=True)
    readAllowed = Column(Boolean)
    writeAllowed = Column(Boolean)
    document_name = Column(String, ForeignKey("documents.name"))
    document = relation(Document, backref = 'permissions')

Then do a simple query with joins:

query = session.query(User, Document, DocumentsPermissions).join(Document).join(DocumentsPermissions)

Answer 3

As @letitbee said, its best practice to assign primary keys to tables and properly define the relationships to allow for proper ORM querying. That being said...

If you're interested in writing a query along the lines of:

SELECT
    user.email,
    user.name,
    document.name,
    documents_permissions.readAllowed,
    documents_permissions.writeAllowed
FROM
    user, document, documents_permissions
WHERE
    user.email = "user@email.com";

Then you should go for something like:

session.query(
    User, 
    Document, 
    DocumentsPermissions
).filter(
    User.email == Document.author
).filter(
    Document.name == DocumentsPermissions.document
).filter(
    User.email == "user@email.com"
).all()

---

If instead, you want to do something like:

SELECT 'all the columns'
FROM user
JOIN document ON document.author_id = user.id AND document.author == User.email
JOIN document_permissions ON document_permissions.document_id = document.id AND document_permissions.document = document.name

Then you should do something along the lines of:

session.query(
    User
).join(
    Document
).join(
    DocumentsPermissions
).filter(
    User.email == "user@email.com"
).all()

One note about that...

query.join(Address, User.id==Address.user_id) # explicit condition
query.join(User.addresses)                    # specify relationship from left to right
query.join(Address, User.addresses)           # same, with explicit target
query.join('addresses')                       # same, using a string

For more information, visit the docs .

Answer 4

Expanding on Abdul's answer, you can obtain a KeyedTuple instead of a discrete collection of rows by joining the columns:

q = Session.query(*User.__table__.columns + Document.__table__.columns).\
        select_from(User).\
        join(Document, User.email == Document.author).\
        filter(User.email == 'someemail').all()

Answer 5

This function will produce required table as list of tuples.

def get_documents_by_user_email(email):
    query = session.query(
       User.email, 
       User.name, 
       Document.name, 
       DocumentsPermissions.readAllowed, 
       DocumentsPermissions.writeAllowed,
    )
    join_query = query.join(Document).join(DocumentsPermissions)

    return join_query.filter(User.email == email).all()

user_docs = get_documents_by_user_email(email)