如何在所有页面上显示一位家长的子页面

Question

I am trying to show the child pages of rugs in the footer in all pages on my wordpress site.

the code in the footer i am using is

            <?php
        global $wp_query;
        $post = $wp_query->post;
        $ancestors = get_post_ancestors($post);
        if( empty($post->post_parent) ) {
            $parent = $post->ID;
        } else {
            $parent = end($ancestors);
        }
        if(wp_list_pages("title_li=&child_of=$parent&echo=0" )) { ?>

        <ul class="footerNav clearfix">
            <?php wp_list_pages("title_li=&child_of=$parent&depth=1" ); ?>
        </ul><!-- #secondary-nav -->

        <?php } ?>

however this only shows the child pages in the footer when you are in the relevant catagory, I would like to see this navigation on all pages.

Thanks,

Sat

here is the link to a page with the footer how i'd like it on all pages

http://satbulsara.com/luke-irwin/rugs/new-in/fishy/

Answer 1

By using

$post = $wp_query->post;
$ancestors = get_post_ancestors($post);

the variable $post is assigned the post the visitor is currently viewing.

If you want a menu of all childs of rugs on all pages, you only need the bottom part of your code. Also, the child_of parameter needs not be assigned via variable, you can input the static page ID of rugs , ie 173 :

<ul class="footerNav clearfix">
    <?php wp_list_pages("title_li=&child_of=173&depth=1&sort_column=post_name" ); ?>
</ul><!-- #secondary-nav -->

These three lines will suffice in generating the menu for you. The if statement you have around it checks whether a the specific parent page has children and only generates an unordered list if that is the case. Since you know it exists in this case, I'd leave it out and save those two lines. I have included the sort_column parameter for sake of completeness - this would give you an alphabetically sorted menu of all rugs.

The code above the if statement is only needed for dynamic menus that change depending on the page the visitor is currently on. Should you ever want to implement such a menu, I'd still go about it differently and think the above is bloated. Simply inserting

<?php $ancestors = get_post_ancestors($post); ?>

into your header.php file will let you generate dynamic menus elsewhere with

<?php if (is_page(173) || in_array(173,$ancestors)) { ?>
    <ul class="subnav">
        <?php wp_list_pages('title_li=&child_of=173&depth=1'); ?>
    </ul>
<?php } ?>

As said above, for your particular case, the fist code block three-liner is sufficient.

Further reference: WP Codex: wp_list_pages