如何将fom字符串转换为十六进制？

Question

I have the following string: s="80" . I need to put this in an unsigned char k[]. The unsigned char should look like this: unsigned char k[]={0x38,0x34}, where 0x38=8 and 0x34=0 unsigned char k[]. The unsigned char should look like this: unsigned char k[]={0x38,0x34}, where 0x38=8 and 0x34=0 These are the hexadecimal values for 8 and 0. How to do this? Need some help!

Please give some code. Thx

I am working on ubuntu c++ code. THX!

I use this for an encryption! I need 0x38 in an unsigned char.PLEASE HELP! Need some code:)

EDIT:

HOW TO OBTAIN THE DEC/CHAR VALUE AND PUT IT IN AN unsigned char k[] ? I've realised that it's ok if in the unsigned char [] i have the dec values {56,52} of the 8 and 0 that i have in the string!

Answer 1

我认为无论您存储的是'8'还是0x39 ，它们在计算机中都将以相同的二进制数字形式出现。

Answer 2

Assuming you want this string converted as ASCII (or UTF-8) it is already in the correct format.

std::string  s="80";

std::cout << "0x" << std::hex << static_cast<int>(s[0]) << "\n";
std::cout << "0x" << std::hex << static_cast<int>(s[1]) << "\n";

If you want it in an int array, then just copy it:

int   data[2];
std::copy(s.begin(), s.end(), data);

Answer 3

I think you do not really understand what you are asking.

The following are synonyms:

std::string s = "\x38\x30";
std::string s = "80";

As the following are synonyms:

char c = '8',  s = '0' ;
char c = s[0], s = s[1];
char c = 0x38, s = 0x30;

It is exactly the same (except if your base encoding is not ASCII). This is not an encryption.

Answer 4

You can try it. I did not write these codes. I found I like you

#include <algorithm>
#include <sstream>
#include <iostream>
#include <iterator>
#include <iomanip>

namespace {
   const std::string test="mahmutefe";
}

int main() {
   std::ostringstream result;
   result << std::setw(2) << std::setfill('0') << std::hex << std::uppercase;
   std::copy(test.begin(), test.end(), std::ostream_iterator<unsigned int>(result, " "));
   std::cout << test << ":" << result.str() << std::endl;
   system("PAUSE");
}

Answer 5

std::string s = "80";
unsigned char * pArray = new unsigned char[ s.size() ];

const char * p = s.c_str();
unsigned char * p2 = pArray;

while( *p )
   *p2++ = *p++;

delete []pArray;

Answer 6

将该字符串转换为char数组，然后从每个char中减去“ 0”。