Javascript正则表达式匹配“ int”

Question

I need a regex to match INT or INT, or INT , to split a String, the String could also contain similar words like INTEGER, INT444, INTEGER2, etc. but they should be ignored.

var str = 'INTEGER INT, INTEGER2 INT , TEST INT';
str = str.split(/INT[\,\)\s]*[^A-Za-z0-0]/gi);

The regex only matches INT, (INT + comma) and INT , (INT + space + comma) but not INT (only the word INT).
Any help?

Answer 1

You mean this?

var str = 'INTEGER INT, INTEGER2 INT , TEST INT';
str = str.split(/INT(?=(?: ?,|$))/gi); // ["INTEGER ", ", INTEGER2 ", " , TEST ", ""]

That's called forward lookahead, more about it here: http://www.javascriptkit.com/javatutors/redev2.shtml

Answer 2

我不确定我是否理解您的问题，但是我认为这就是您的要求。

INT,|INT |INT(?![A-Za-z0-9])

Answer 3

How about :

/INT\b\s*,?/

on your example, it gives :

["INTEGER ", " INTEGER2 ", " TEST "]

Answer 4

Probably you are looking for word boundaries \\b

\bINT\b

\\b will match the boundary between a character included in \\w and other characters.